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Hyperstack.on_server? can do much better please

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#345 1 則留言 1 個 reaction 已指派 0 人 在 GitHub 檢視

還沒有人認領這個 Issue。

評估

難度
5/5
預估耗時
一週以上
新手友好度
25/100
Issue 類型
功能
描述清晰度
需要釐清
活躍度
停滯
技術堆疊
rails, ruby
領域
backend

研究方向

先追蹤 Hyperstack.on_server? 以及 issue 中描述的 initializer 覆寫,接著比較其中提到的 simple_poller 和 Action Cable 模式。完成的標準是:使用 forward_messages_to_server? 取代對伺服器位置的假設,並透過設定或行為檢查避免不必要的轉送,同時保留必要的廣播。

由索引模型根據 Issue 內容生成。

描述

enhancement needs doc

Currently Hyperstack.on_server? returns false if you not on the rails server (i.e. on the console or on in a sidekiq worker).

The system uses this to decide if it needs to forward any broadcasts to the server from, under the assumption that if you are not on the server you do not have access to the broadcast mechanism.

This assumption is pretty weak. The following are known cases where it doesn't matter:

you are using simple_poller (in this case you are going to shove the message into a queue, and wait for the next poll)

you are using action_cable NOT in async mode. (i.e. the connection data is stored in a database, not in the servers memory)

Not tested is pusher, and actually not tested (but I'm sure it would work is action_cable and redis)

Soooo...

This method should be called: forward_messages_to_server?
and should check to see if we have to forward it, by a combination of checking configuration and/or checking actual behavior.

Why should I care?

Because if you are using a lot of outside processes to do stuff, then you are adding unneeded overhead forwarding this stuff to the server.

The current work around is very simple: Just add this line to the hyperstack initializer

def Hyperstack.on_server?; true; end

主要語言
JavaScript
星號
538
分支
41
PR 合併指標
30 天內沒有已合併 PR

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