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Zeroize performance on u8 arrays

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#743 23 comments 0 reactions 0 assignees View on GitHub

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Assessment

Difficulty
5/5
Estimated time
Over a week
Newbie friendliness
25/100
Issue type
Bug
Clarity
Needs clarification
Activity status
Stale
Tech stack
rust
Domain
performance

Research direction

Start with the Rust Playground benchmark linked in the issue and inspect the generated assembly for zeroize on [u8; 32]. Compare the current output with the inline-assembly and larger-type approaches described in the report. Done requires an agreed optimization or documentation change, with its performance and code-size impact verified.

Written by the indexing model from the issue text.

Description

I inspected the generated assembly code and benchmarked zeroize for [u8; 32] on x86_64 and found it quite inefficient, storing one byte at a time:

https://play.rust-lang.org/?version=stable&mode=release&edition=2021&gist=3f44f4b90e6af0eac0dcb1f649390329

On my Ryzen CPU, it takes ~7.8324 ns, or ~1cpb. Binary code size is also quite large.

Using inline assembly (just stabilized in 1.59) and SSE2, zeroing a [u8; 32] takes just 3 instructions and ~492.87 ps (~16 bytes per cycle):

let mut buf: [u8; 32];
core::arch::asm!(
    "xorps {zero}, {zero}",
    "movups {zero}, ({ptr})",
    "movups {zero}, 16({ptr})",
    zero = out(xmm_reg) _,
    ptr = in(reg) &mut buf,
    options(att_syntax, nostack, preserves_flags),
);

So it might be something worth optimizing/documenting.

If you do not want to use inline assembly, maybe you should encourage using larger types or SIMD types, e.g., [u64; 4] or [__m128; 2] instead of [u8; 32]. Using write_volatile on *mut __m128 generates equally compact and efficient code as the assembly code above.

Dominant language
Rust
Stars
674
Forks
170
Avg merge
1d 12h
Merged PRs (30d)
10

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