Hacktoberfest 2026：维护者为十月标记出来的 issue，仍然开放、适合新手。 浏览 Hacktoberfest issue

There's some way to set the `source` field param for nested fields?

未关闭
#1,439 3 条评论 0 个 reaction 已指派 0 人 在 GitHub 查看

还没有人认领这个 Issue。

评估

难度
3/5
预计耗时
1-2 天
新手友好度
35/100
Issue 类型
功能
描述清晰度
基本清楚
活跃度
停滞
技术栈
python
领域
api, backend

调研方向

从 graphene/types/field.py 中引用的 source 解析代码开始，追踪 DjangoObjectType 字段如何使用 source 值。将 actor__login 示例与当前的自定义 resolver 替代方案进行比较；当预期的嵌套关系行为得到支持，或限制和预期的 resolver 方案得到文档说明时，即视为完成。

由索引模型根据 Issue 内容生成。

描述

Context

I'm currently trying to set my model user User subfield user.actor.id as field source of my DjangoObjectType.

This happens because there's other kind of users within the application like an Organization or even a Bot (all of them are actors).

Example

Lets define a custom Type:

class User(DjangoObjectType):
    class Meta:
        model = UserModel
        exclude = ['actor']
        filter_fields = ['actor__login']
        interfaces = [graphene.relay.Node]
        skip_registry = True

    # The login field is originated from `actor` relationship, not from the user model itself.
    # It doesn't work, actor__login is interpreted as user field [user.actor__login] not [user.actor.login].
    login = graphene.Field(graphene.String, source='actor__login')
    # ...

In the example above I define the login field source as source='actor__login' but I saw that here we're using getattr function to resolve the source so it's currently impossible to set the field without defining a custom resolver.

https://github.com/graphql-python/graphene/blob/dfece7f65d4bad51a87a8e9f03f9acef1e25d3f8/graphene/types/field.py#L16-L20

I would like to know if there's an alternative solution to select a subfield like the example or we're forced to create a custom resolver by using the resolver=lambda _, __: ... arg or the class method declaration.

Thanks for the hard work and the library!

主要语言
Python
星标
8.2k
派生
818
30 天内没有已合并 PR

贡献指南

这个仓库没有索引到贡献指南

从这里开始

  1. 先读完整个 Issue，再读项目的贡献指南。
  2. 在 Issue 下留言说明你要接手 —— 这能避免两个人做同样的事。
  3. Fork 仓库，在一个分支上完成修改。
  4. 提交 Pull Request，并在描述里引用这个 Issue 编号。

graphql-python/graphene 的其他 Issue

查看 graphql-python/graphene 的全部 Issue

相似的 Issue

更多 Python Issue

把新 issue 发到你的邮箱

精选适合新手参与的 GitHub issue 摘要。