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Views with CTEs parsed incorrectly

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评估

难度
4/5
预计耗时
3-5 天
新手友好度
48/100
Issue 类型
缺陷
描述清晰度
基本清楚
活跃度
冷清
技术栈
mysql, php, sql
领域
databases

调研方向

从链接的 test.php 脚本开始,并使用 phpmyadmin/sql-parser 5.11.1 重现输出。跟踪包含 CTEs 的多个 CREATE VIEW 语句是如何被解析的,然后为无括号形式添加覆盖测试,并验证每个视图在不需要括号的情况下仍保持独立且正确。

由索引模型根据 Issue 内容生成。

描述

bug

Hi, parser has been working great for the most part but I ran into an issue today where I have multiple views with CTEs that get mixed together by the parser. I found that if I put parentheses around each view body definition the issue goes away, but MySQL does not require this.

Here is a minimal test script that demonstrates the issue:
test.php

Output from the test script on my machine follows. I am using phpmyadmin/sql-parser version 5.11.1 installed via composer.

-- SQL A:
CREATE VIEW view1 AS
WITH foo AS (SELECT abc FROM foo_table),
bar AS (SELECT id, xyz FROM bar_table)
SELECT foo.id AS id, foo.abc AS abc, bar.xyz AS xyz
FROM foo LEFT JOIN bar USING (id)
ORDER BY foo.abc, bar.xyz;

CREATE VIEW view2 AS
WITH foo AS (SELECT id, abc FROM foo_table),
bar AS (SELECT id, xyz FROM bar_table)
SELECT foo.id AS id, foo.abc AS abc, bar.xyz AS xyz
FROM foo LEFT JOIN bar USING (id)
ORDER BY foo.abc, bar.xyz;

-- Result A:
-- create VIEW view1
CREATE VIEW view1  AS WITH foo AS (SELECT abc FROM foo_table), bar AS (SELECT id, xyz FROM bar_table) SELECT foo.id AS `id`, foo.abc AS `abc`, bar.xyz AS `xyz` FROM foo LEFT JOIN bar USING (id) ORDER BY foo.abc ASC, bar.xyz ASCCREATE VIEW view2  AS WITH foo AS (SELECT id, abc FROM foo_table), bar AS (SELECT id, xyz FROM bar_table) SELECT foo.id AS `id`, foo.abc AS `abc`, bar.xyz AS `xyz` FROM foo LEFT JOIN bar USING (id) ORDER BY foo.abc ASC, bar.xyz ASC


-- SQL B:
CREATE VIEW view1 AS (
WITH foo AS (SELECT abc FROM foo_table),
bar AS (SELECT id, xyz FROM bar_table)
SELECT foo.id AS id, foo.abc AS abc, bar.xyz AS xyz
FROM foo LEFT JOIN bar USING (id)
ORDER BY foo.abc, bar.xyz);

CREATE VIEW view2 AS (
WITH foo AS (SELECT id, abc FROM foo_table),
bar AS (SELECT id, xyz FROM bar_table)
SELECT foo.id AS id, foo.abc AS abc, bar.xyz AS xyz
FROM foo LEFT JOIN bar USING (id)
ORDER BY foo.abc, bar.xyz);

-- Result B:
-- create VIEW view1
CREATE VIEW view1  AS  (
WITH foo AS (SELECT abc FROM foo_table),
bar AS (SELECT id, xyz FROM bar_table)
SELECT foo.id AS id, foo.abc AS abc, bar.xyz AS xyz
FROM foo LEFT JOIN bar USING (id)
ORDER BY foo.abc, bar.xyz)
-- create VIEW view2
CREATE VIEW view2  AS  (
WITH foo AS (SELECT id, abc FROM foo_table),
bar AS (SELECT id, xyz FROM bar_table)
SELECT foo.id AS id, foo.abc AS abc, bar.xyz AS xyz
FROM foo LEFT JOIN bar USING (id)
ORDER BY foo.abc, bar.xyz)
主要语言
PHP
星标
485
派生
119
PR 合并指标
30 天内没有已合并 PR

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