Hacktoberfest 2026: as issues que os mantenedores marcaram para outubro, abertas e boas para iniciantes. Ver issues do Hacktoberfest

Views with CTEs parsed incorrectly

Aberta
  • Algo errado?
#639 2 comentários 0 reações 0 responsáveis Ver no GitHub

@oiahoon já está trabalhando nisso.

Desde 12/7/2026.

  • #660 de @oiahoon — aberto

Avaliação

Dificuldade
4/5
Tempo estimado
3-5 dias
Facilidade para iniciantes
48/100
Tipo de issue
Bug
Clareza
Razoavelmente clara
Status de atividade
Pouca atividade
Stack de tecnologia
mysql, php, sql
Domínio
databases

Direção de pesquisa

Comece pelo script test.php vinculado e reproduza a saída usando phpmyadmin/sql-parser 5.11.1. Rastreie como várias instruções CREATE VIEW contendo CTEs são analisadas; em seguida, adicione cobertura para a forma sem parênteses e verifique se cada view permanece separada e correta sem exigir parênteses.

Escrita pelo modelo de indexação a partir do texto da issue.

Descrição

bug

Hi, parser has been working great for the most part but I ran into an issue today where I have multiple views with CTEs that get mixed together by the parser. I found that if I put parentheses around each view body definition the issue goes away, but MySQL does not require this.

Here is a minimal test script that demonstrates the issue:
test.php

Output from the test script on my machine follows. I am using phpmyadmin/sql-parser version 5.11.1 installed via composer.

-- SQL A:
CREATE VIEW view1 AS
WITH foo AS (SELECT abc FROM foo_table),
bar AS (SELECT id, xyz FROM bar_table)
SELECT foo.id AS id, foo.abc AS abc, bar.xyz AS xyz
FROM foo LEFT JOIN bar USING (id)
ORDER BY foo.abc, bar.xyz;

CREATE VIEW view2 AS
WITH foo AS (SELECT id, abc FROM foo_table),
bar AS (SELECT id, xyz FROM bar_table)
SELECT foo.id AS id, foo.abc AS abc, bar.xyz AS xyz
FROM foo LEFT JOIN bar USING (id)
ORDER BY foo.abc, bar.xyz;

-- Result A:
-- create VIEW view1
CREATE VIEW view1  AS WITH foo AS (SELECT abc FROM foo_table), bar AS (SELECT id, xyz FROM bar_table) SELECT foo.id AS `id`, foo.abc AS `abc`, bar.xyz AS `xyz` FROM foo LEFT JOIN bar USING (id) ORDER BY foo.abc ASC, bar.xyz ASCCREATE VIEW view2  AS WITH foo AS (SELECT id, abc FROM foo_table), bar AS (SELECT id, xyz FROM bar_table) SELECT foo.id AS `id`, foo.abc AS `abc`, bar.xyz AS `xyz` FROM foo LEFT JOIN bar USING (id) ORDER BY foo.abc ASC, bar.xyz ASC


-- SQL B:
CREATE VIEW view1 AS (
WITH foo AS (SELECT abc FROM foo_table),
bar AS (SELECT id, xyz FROM bar_table)
SELECT foo.id AS id, foo.abc AS abc, bar.xyz AS xyz
FROM foo LEFT JOIN bar USING (id)
ORDER BY foo.abc, bar.xyz);

CREATE VIEW view2 AS (
WITH foo AS (SELECT id, abc FROM foo_table),
bar AS (SELECT id, xyz FROM bar_table)
SELECT foo.id AS id, foo.abc AS abc, bar.xyz AS xyz
FROM foo LEFT JOIN bar USING (id)
ORDER BY foo.abc, bar.xyz);

-- Result B:
-- create VIEW view1
CREATE VIEW view1  AS  (
WITH foo AS (SELECT abc FROM foo_table),
bar AS (SELECT id, xyz FROM bar_table)
SELECT foo.id AS id, foo.abc AS abc, bar.xyz AS xyz
FROM foo LEFT JOIN bar USING (id)
ORDER BY foo.abc, bar.xyz)
-- create VIEW view2
CREATE VIEW view2  AS  (
WITH foo AS (SELECT id, abc FROM foo_table),
bar AS (SELECT id, xyz FROM bar_table)
SELECT foo.id AS id, foo.abc AS abc, bar.xyz AS xyz
FROM foo LEFT JOIN bar USING (id)
ORDER BY foo.abc, bar.xyz)
Linguagem predominante
PHP
Estrelas
486
Forks
120
Merge médio
1d 17h
PRs com merge (30d)
5

Preparar o ambiente

Primeiros passos

  1. Leia a issue inteira e depois o guia de contribuição do projeto.
  2. Comente na issue dizendo que vai assumir — evita que duas pessoas façam o mesmo trabalho.
  3. Faça um fork do repositório e trabalhe em uma branch.
  4. Abra um pull request que referencie o número da issue.

Mais de phpmyadmin/sql-parser

Todas as issues de phpmyadmin/sql-parser

Issues semelhantes

Mais issues de PHP

Receba novas issues na sua caixa de entrada

Um resumo curto de issues do GitHub para quem está começando.