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Specialization of `N0f16` -> `Float16` conversion

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还没有人认领这个 Issue。

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难度
3/5
预计耗时
1-2 天
新手友好度
55/100
Issue 类型
缺陷
描述清晰度
基本清楚
活跃度
活跃
技术栈
julia
领域
backend

调研方向

The issue links to the N0f8 to Float16 conversion in src/normed.jl around lines 145–147. Read that implementation and compare its behavior with the N0f16 conversion; reproduce the two reported mismatches, then determine what conversion change would make the results match the BigFloat reference. Done means those cases convert to the expected Float16 values.

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描述

I have long suggested considering the use of Float16 or BFloat16 for image processing tasks where there is a risk of overflow.
I personally believe that, as a result of the increasing use of GPUs in the Julia ecosystem, we find ourselves in the ironic situation where GPU support in the graphics field has lagged behind.

Even if there are counterarguments regarding my understanding of the situation, I don't think there's any problem with improving the conversion to Float16.

The current N0f8->Float16 conversion is performed via Float32, which isn't too bad.
https://github.com/JuliaMath/FixedPointNumbers.jl/blob/d62abf3a5f2f0e99e63e22eeb4835eff717c9086/src/normed.jl#L145-L147

julia> for i in 0x00:0xff
           f = Float16(i/big"255")
           n = Float16(reinterpret(N0f8, i))
           f === n && continue
           @show i, f, n
       end

On the other hand, converting from N0f16 to Float16 results in an error of 1ULP (0.5ULP).

julia> for i in 0x0000:0xffff
           f = Float16(i/big"65535")
           n = Float16(reinterpret(N0f16, i))
           f === n && continue
           @show i, f, n
       end
(i, f, n) = (0xffaf, Float16(0.9985), Float16(0.999))
(i, f, n) = (0xffef, Float16(0.9995), Float16(1.0))
主要语言
Julia
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派生
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  • 阅读贡献指南

从这里开始

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  3. Fork 仓库,在一个分支上完成修改。
  4. 提交 Pull Request,并在描述里引用这个 Issue 编号。

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