Hamiltonian expectation value in one call
Nobody has claimed this yet.
Assessment
- Difficulty
- 4/5
- Estimated time
- 3-5 days
- Newbie friendliness
- 48/100
- Issue type
- Feature
- Clarity
- Mostly clear
- Activity status
- Active
- Domain
- backend, performance
Research direction
Start by locating the Rust code that parses Pauli terms and computes qc.expectation(terms), then trace how Python exposes that API. Check how terms are represented and how gradient() accepts inputs; the issue proposes a reusable PauliSum and sharing amplitude passes by flip mask. Done means a Hamiltonian object can be reused with expectation() and passed to gradient(), with the grouped computation described in the issue.
Written by the indexing model from the issue text.
Description
What you want to do
coeffs @ qc.expectation(terms) works, but it builds an array of one value per term, and there's
no single object for a Hamiltonian that can be reused across calls or passed to gradient() (M3).
Implementation notes
- Parse once in Rust. Terms with the same X/Y positions (the same
flipmask) can share one pass
over the amplitudes, which cuts passes from (number of terms) to (number of distinct flip masks).
For example, all Z-only terms share one pass.
What it could look like
H = qsengine.PauliSum({"ZZI": 1.0, "IZZ": 1.0, "XII": -0.5})
qc.expectation(H) # -> float
Contributing
- I would like to open a pull request for this (see CONTRIBUTING.md).
- Dominant language
- Rust
- Stars
- 1
- Forks
- 0
- Avg merge
- 12m
- Merged PRs (30d)
- 4
Getting set up
- No Dockerfile or Docker Compose file
- No pull request template
- Read the contributing guide
First steps
- Read the whole issue, then the project's contributing guide.
- Comment on the issue to say you are picking it up — it saves two people doing the same work.
- Fork the repository and make your change on a branch.
- Open a pull request that references the issue number.
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