[Bug]: async generator aclose() does not suspend on an await in a finally block
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まだ誰も着手していません。
評価
調査の方向性
Start with GraalPy’s async-generator implementation and the CPython test_asyncgen cases named in the report, especially test_async_gen_asyncio_aclose_07, which reproduces the failure. Compare how aclose() handles a yielded value during an await in a finally block with the expected CPython behavior. Done means the yielded value reaches the caller of send(), the generator resumes only on the next send, and the listed tests pass.
索引モデルが issue の本文から書いたものです。
説明
Describe the bug
When aclose() throws GeneratorExit into an async generator, an await in the generator's finally block does not suspend. GraalPy discards the value that the awaited object yields and resumes the generator at once. The full cleanup then runs inside one send() call on the aclose() awaitable.
CPython passes the yielded value out to the caller of send(), so the event loop sees it. On GraalPy the value never reaches the event loop. With asyncio, any await on a future in a finally block during aclose() fails with RuntimeError: await wasn't used with future.
Operating system
Linux
CPU architecture
x86_64
GraalPy version
GraalPy 3.13.14 (GraalVM CE Native 25.3.4.1), also GraalPy 3.13.14 (GraalVM CE Native 25.4.4.1.1)
JDK version
No response
Context configuration
Minimal reproducer without asyncio:
class Suspend:
def __await__(self):
print(" Suspend: about to yield")
yield "suspended"
print(" Suspend: resumed")
async def agen():
try:
yield 1
finally:
print(" finally: before await")
await Suspend()
print(" finally: after await")
g = agen()
try:
g.__anext__().send(None)
except StopIteration as s:
print("first", s.value)
c = g.aclose()
for i in range(3):
try:
print("send %d ->" % i, repr(c.send(None)))
except StopIteration:
print("send %d -> StopIteration" % i)
break
Output on GraalPy:
first 1
finally: before await
Suspend: about to yield
Suspend: resumed
finally: after await
send 0 -> StopIteration
Reproducer with asyncio:
import asyncio
async def agen():
try:
yield 1
finally:
await asyncio.sleep(0.01)
print("cleanup done")
async def main():
g = agen()
await g.__anext__()
await g.aclose()
asyncio.run(main())
On GraalPy this raises RuntimeError: await wasn't used with future (see the stack trace below).
Steps to reproduce
Minimal reproducer without asyncio:
class Suspend:
def __await__(self):
print(" Suspend: about to yield")
yield "suspended"
print(" Suspend: resumed")
async def agen():
try:
yield 1
finally:
print(" finally: before await")
await Suspend()
print(" finally: after await")
g = agen()
try:
g.__anext__().send(None)
except StopIteration as s:
print("first", s.value)
c = g.aclose()
for i in range(3):
try:
print("send %d ->" % i, repr(c.send(None)))
except StopIteration:
print("send %d -> StopIteration" % i)
break
Output on GraalPy:
first 1
finally: before await
Suspend: about to yield
Suspend: resumed
finally: after await
send 0 -> StopIteration
Reproducer with asyncio:
import asyncio
async def agen():
try:
yield 1
finally:
await asyncio.sleep(0.01)
print("cleanup done")
async def main():
g = agen()
await g.__anext__()
await g.aclose()
asyncio.run(main())
On GraalPy this raises RuntimeError: await wasn't used with future (see the stack trace below).
Expected behavior
Same as CPython 3.13. The first send() on the aclose() awaitable returns the value that the await yields. The generator resumes only on the next send():
first 1
finally: before await
Suspend: about to yield
send 0 -> 'suspended'
Suspend: resumed
finally: after await
send 1 -> StopIteration
The asyncio reproducer prints cleanup done and exits with no error.
Stack trace
Traceback (most recent call last):
File "repro_asyncio.py", line 5, in agen
yield 1
GeneratorExit
During handling of the above exception, another exception occurred:
Traceback (most recent call last):
File "repro_asyncio.py", line 15, in <module>
asyncio.run(main())
File "<graalpy>/lib/python3.13/asyncio/runners.py", line 196, in run
return runner.run(main)
File "<graalpy>/lib/python3.13/asyncio/runners.py", line 119, in run
return self._loop.run_until_complete(task)
File "<graalpy>/lib/python3.13/asyncio/base_events.py", line 725, in run_until_complete
return future.result()
File "<graalpy>/lib/python3.13/asyncio/futures.py", line 199, in result
raise self._exception.with_traceback(self._exception_tb)
File "<graalpy>/lib/python3.13/asyncio/tasks.py", line 304, in __step_run_and_handle_result
result = coro.send(None)
File "repro_asyncio.py", line 13, in main
await g.aclose()
File "repro_asyncio.py", line 7, in agen
await asyncio.sleep(0.01)
File "<graalpy>/lib/python3.13/asyncio/tasks.py", line 721, in sleep
return await future
File "<graalpy>/lib/python3.13/asyncio/futures.py", line 288, in __await__
raise RuntimeError("await wasn't used with future")
RuntimeError: await wasn't used with future
Additional context
The CPython tests in test_asyncgen that await in finally during aclose() are not in GraalPy's passing list (graalpython/com.oracle.graal.python.test/src/tests/unittest_tags/test_asyncgen.txt): test_async_gen_asyncio_aclose_07, aclose_08, gc_aclose_09 and aclose_12. aclose_07 fails with the same RuntimeError when run on its own.
Found with a Cython test that now excludes this case on GraalPy: https://github.com/cython/cython/pull/8028
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