Clarify the valid use locations of `typing.Concatenate`

Beginne mit dem Abschnitt zu benutzerdefinierten generischen Klassen in der typing-Spezifikation und der CPython-Dokumentation zu typing.Concatenate; vergleiche anschließend die Beispiele und das gemeldete Verhalten von mypy, pyright und ty. Prüfe die verknüpften Concatenate-Suchnotizen und ermittle, welche Verwendungsstellen gültig sind; abgeschlossen ist die Aufgabe, wenn die typing-Spezifikation und die CPython-Dokumentation die unterstützten Formen und die Einschränkung für verschachteltes Concatenate eindeutig beschreiben.

In python/cpython#142965, it was reported that the documentation of typing.Concatenate is "incorrect" (documentation that originates back to python/cpython#24000).

@A5rocks, in your example, Concatenate[int, P_2] somewhat finally lands as a first argument to Callable, just indirectly.
This snippet previously defined:

P_2 = ParamSpec("P_2")

class X(Generic[T, P]):
  f: Callable[P, int]
  x: T

Similar example is included in the typing spec:

https://typing.python.org/en/latest/spec/generics.html#user-defined-generic-classes

class X[T, **P]:
    f: Callable[P, int]
    x: T

# (...)
def accept_concatenate[**P](x: X[int, Concatenate[int, P]]) -> str: ...  # Accepted

However, it seems that the current situation (confirmed with mypy, pyright and ty) is that you can use Concatenate in all valid locations of ParamSpec except directly in a Concatenate. I.e., you can't do Concatenate[int, Concatenate[str, P]]), but you can (besides passing Concatenate form as the first argument to Callable):

1. Accumulate Concatenates as ParamSpecs

from collections.abc import Callable
from typing import Concatenate

type Y[**P] = Callable[Concatenate[int, P], None]
type X[**P] = Y[Concatenate[int, P]]

def foo(f: X[str]) -> None:
    reveal_type(f)
    # mypy: def (builtins.int, builtins.int, builtins.str)
    # pyright: (int, int, str) -> None
    # ty: (...) -> None

2. Bind Concatenates to user-defined generics as ParamSpecs

class X[T, **P]:
    f: Callable[P, int]
    x: T

def accept_concatenate[**P](x: X[int, Concatenate[int, P]]) -> str: ...

3. Use Concatenate as a type argument to tuple -- is this correct?

from typing import Concatenate

def c(t: tuple[Concatenate[int, ...]]) -> None:
    reveal_type(c)
    # mypy: def (t: tuple[[builtins.int, *Any, **Any]])
    # pyright: (t: tuple[Concatenate[int, ...]]) -> None
    # ty: def c(t: tuple[@Todo]) -> None

I've found this mostly by poking around -- I haven't analyzed the actual implementations (yet).
I'll continue to investigate this from these searches.

I think that the valid use locations of Concatenate should be clarified in the typing spec and then in the CPython docs.

Is there anything else I overlooked? CC @JelleZijlstra @AlexWaygood