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Feature: Timeout on command execution

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还没有人认领这个 Issue。

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难度
4/5
预计耗时
3-5 天
新手友好度
42/100
Issue 类型
功能
描述清晰度
基本清楚
活跃度
停滞
技术栈
docker, python
领域
devops, testing

调研方向

从 DockerContainer.exec 和 docs/features/executing_commands.md 开始，然后将文档中的 timeout 示例与 docker-py Container.exec_run 及其限制进行比较。当 exec() 接受 timeout、在超过期限时引发 TimeoutError，并且不会让 test run 无限期阻塞时，即视为完成。

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描述

🚀 enhancement

What are you trying to do?

The DockerContainer.exec() method does not support a timeout parameter, even though the documentation explicitly describes this functionality:

with GenericContainer("alpine:latest") as container:
    try:
        exit_code, output = container.exec(
            ["sleep", "10"],
            timeout=5  # Timeout in seconds
        )
    except TimeoutError:
        print("Command timed out")

However, the actual implementation simply forwards to docker-py's exec_run without accepting any additional keyword arguments:

def exec(self, command: Union[str, list[str]]) -> ExecResult:
    if not self._container:
        raise ContainerStartException("Container should be started before executing a command")
    return self._container.exec_run(command)

We'd like exec() to support a timeout so that commands that hang or take too long don't block test runs indefinitely.

Why should it be done this way?

Without a timeout, any exec() call that hangs (e.g. a command waiting on a resource that never becomes available) will block the test process forever with no way to recover other than killing the process externally.

Unfortunately this isn't a simple pass through - the underlying docker-py Container.exec_run() also does not expose a timeout parameter. So this would need a client-side implementation, for example wrapping the call with concurrent.futures.ThreadPoolExecutor and a deadline, or using exec_run(socket=True) with a socket-level timeout.

Just like the timeout for a subprocess.run run doesn't guarantee closing the process after the timeout, so will this.

I'm happy to open a PR for this, but wanted to gain agreement on the issue first before submitting code.

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