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Proposal: reverse continue

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难度
5/5
预计耗时
一周以上
新手友好度
30/100
Issue 类型
功能
描述清晰度
基本清楚
活跃度
停滞
技术栈
ruby
领域
devtools

调研方向

Start by running the shown rdbg session with record on, the breakpoint, and continue back to understand the proposed reverse-debugging flow. The issue mentions no repository files or tests; done would be implementing and documenting a reverse-continue workflow that lands at the earlier state matching a breakpoint or condition.

由索引模型根据 Issue 内容生成。

描述

Your proposal

Here's a simplistic piece of code:

# test.rb
def foo(a, b)
  a.x = nil if b == 5
end

a = Struct.new(:x).new(10)

10.times do |i|
  foo(a, i)
  puts a.x + i
end

It has a bug and will crash when i is 5:

$ ruby test.rb
10
11
12
13
14
test.rb:9:in `block in <main>': undefined method `+' for nil (NoMethodError)

  puts a.x + i
           ^
	from <internal:numeric>:237:in `times'
	from test.rb:9:in `<main>'

We can do this:

$ rdbg test.rb        
[1, 10] in test.rb
=>   1| def foo(a, b)
     2|   a.x = nil if b == 5
     3| end
     4| 
     5| a = Struct.new(:x).new(10)
     6| 
     7| 10.times do |i|
     8|   foo(a, i)
     9|   puts a.x + i
    10| end
=>#0	<main> at test.rb:1
(rdbg) break 9 if: a.x == nil    # command
#0  BP - Line  /Users/loic.nageleisen/test.rb:9 (line) if: a.x == nil
(rdbg) record on    # command
Recorder for #<Thread:0x000000010292b0c8 run>: on (0 records)
(rdbg) continue    # command
10
11
12
13
14
[4, 10] in test.rb
     4| 
     5| a = Struct.new(:x).new(10)
     6| 
     7| 10.times do |i|
     8|   foo(a, i)
=>   9|   puts a.x + i
    10| end
=>#0	block {|i=5|} in <main> at test.rb:9
  #1	Integer#times at <internal:numeric>:237
  # and 1 frames (use `bt' command for all frames)

Stop by #0  BP - Line  /Users/loic.nageleisen/test.rb:9 (line) if: a.x == nil
(rdbg) step back    # command
[replay] [4, 10] in test.rb
[replay]      4| 
[replay]      5| a = Struct.new(:x).new(10)
[replay]      6| 
[replay]      7| 10.times do |i|
[replay]      8|   foo(a, i)
[replay] =>   9|   puts a.x + i
[replay]     10| end
[replay] =>#0	block {|i=5|} in <main> at test.rb:9
[replay]   #1	Integer#times at <internal:numeric>:237
[replay]   # and 1 frames (use `bt' command for all frames)
(rdbg) step back    # command
[replay] [1, 10] in test.rb
[replay]      1| def foo(a, b)
[replay] =>   2|   a.x = nil if b == 5
[replay]      3| end
[replay]      4| 
[replay]      5| a = Struct.new(:x).new(10)
[replay]      6| 
[replay]      7| 10.times do |i|
[replay]      8|   foo(a, i)
[replay]      9|   puts a.x + i
[replay]     10| end
[replay] =>#0	Object#foo(a=#<struct  x=nil>, b=5) at test.rb:2
[replay]   #1	block {|i=5|} in <main> at test.rb:8
[replay]   # and 2 frames (use `bt' command for all frames)
(rdbg) 

And there we find the line that caused our bug.

Sadly many a time the code is much more sizeable and complex, and it's not that easy to go back step by step.

I would like to propose possible usage:

break 9 if: a.x == nil
record on
continue
# <= breakpoint hit
break if: a.x != nil           # or `break a.x=`
continue back                  # or `reverse continue`
# <= lands on line 3
break 9 if: a.x == nil
record on
continue
# <= breakpoint hit
watch a.x
continue back
# <= lands on line 3
break 9 if: a.x == nil
record on
continue
# <= breakpoint hit
step back until a.x != nil             # or `reverse until a.x != nil`
# <= lands on line 3

Both would automate going from the issue occurence back until a specific condition is met.

Additional context

Inspired by rr's reverse-continue and watch -l

主要语言
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