Hacktoberfest 2026:维护者为十月标记出来的 issue,仍然开放、适合新手。 浏览 Hacktoberfest issue

A regex literal that starts a statement is parsed as division, and the formatter removes the parentheses that prevent it

未关闭
#8,688 0 条评论 0 个 reaction 已指派 0 人 在 GitHub 查看

维护者通常 1 天内回复

还没有人认领这个 Issue。

评估

难度
4/5
预计耗时
3-5 天
新手友好度
68/100
Issue 类型
缺陷
描述清晰度
描述清楚
活跃度
活跃
技术栈
ocaml
领域
compilers, tooling

调研方向

Start with compiler/syntax/src/res_core.ml, especially parse_binary_expr, and reproduce the issue with npx rescript format src/A.res followed by npx rescript build. Trace how a regex literal at the start of a statement is parsed and how its parentheses are formatted. Done means the shown source remains parseable after formatting and the build succeeds.

由索引模型根据 Issue 内容生成。

描述

Thank you for filing! Check list:

  • Is it a bug? Usage questions should often be asked in the forum instead.
  • Concise, focused, friendly issue title & description.
  • A minimal, reproducible example.
  • OS and browser versions, if relevant.
  • Is it already fixed in master? Instructions

A regex literal at the start of a statement, on the line after another statement, is parsed as a division that continues the previous line, so the file does not parse.
rescript format produces exactly this form from code that parses: it removes the parentheses around the literal.

Snippet

src/A.res:

let f = s => {
  let t = s
  (/a/)->RegExp.test(t)
}
npx rescript format src/A.res
cat src/A.res
npx rescript build

Actual

let f = s => {
  let t = s
  /a/->RegExp.test(t)
}
Cleaned 0/0
Error in check:

  Syntax error!
  /path/to/check/src/A.res:3:6-7

  1 │ let f = s => {
  2 │   let t = s
  3 │   /a/->RegExp.test(t)
  4 │ }
  5 │ 

  Did you forget to write an expression here?


Incremental build failed. Error:   Could not parse Source Files

The formatted form fails the same way when written by hand, and so does a regex literal after an expression statement (Console.log(s)) or after a top-level let.

The formatter gives the same result for the other spellings that parse:

  • ; at the end of the line before the literal (let t = s;) is removed;
  • on 12.3.1, %re("/a/")->RegExp.test(t) becomes /a/->RegExp.test(t).

These spellings parse and keep their form after formatting:

  • the literal as the first statement of the block;
  • the literal as a call argument: RegExp.test(/a/, t);
  • the literal bound to a name first: let r = /a/.

Expected

The file parses: / at the start of a statement starts a regex literal.
If that is not possible, the formatter keeps the parentheses (or the ;) in front of such a literal.

Possible cause: in parse_binary_expr (compiler/syntax/src/res_core.ml), Minus | MinusDot | LessThan | Percent on a new line with no whitespace after it is not taken as a binary operator.
Forwardslash has no such case, so / on a new line always continues the expression on the line before.

Worked in ReScript 11

ReScript 11.1.4 has no regex literals, and its formatter keeps %re:

let f = s => {
  let t = s
  %re("/a/")->Js.Re.test_(t)
}

The same commands print the file unchanged and build it:

let f = s => {
  let t = s
  %re("/a/")->Js.Re.test_(t)
}
>>>> Start compiling
Dependency Finished
rescript: [1/3] src/A.ast
rescript: [2/3] src/A.d
rescript: [3/3] src/A.cmj
>>>> Finish compiling 19 mseconds

Environment

  • ReScript 12.3.1, 13.0.0-alpha.6, and master 58c6c89 (from pkg.pr.new, reports 13.0.0-alpha.7): the same result on all three.
  • Node.js 24.9.0
  • Linux x86_64

Context

We hit it when rescript format 12.3.1 rewrote %re("/^[0-9\.,+-]*$/")->RegExp.test(str) ? Some(str) : None, which came right after a let line in a block.

Workaround

Pass the literal as an argument (RegExp.test(/a/, t)) or bind it with let first.

主要语言
OCaml
星标
7.5k
派生
485
平均合并
1 天 6 小时
30 天内合并 PR
52

环境准备

从这里开始

  1. 先读完整个 Issue,再读项目的贡献指南。
  2. 在 Issue 下留言说明你要接手 —— 这能避免两个人做同样的事。
  3. Fork 仓库,在一个分支上完成修改。
  4. 提交 Pull Request,并在描述里引用这个 Issue 编号。

rescript-lang/rescript 的其他 Issue

查看 rescript-lang/rescript 的全部 Issue

相似的 Issue

更多 Compilers Issue

把新 issue 发到你的邮箱

精选适合新手参与的 GitHub issue 摘要。