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Solution for throttle decorator is incorrect. (Decorators and forwarding, call/apply)

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javascript
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documentation

调研方向

从链接的教程“Decorators and forwarding, call/apply”部分中的 throttle decorator 示例开始,并复现所提供的 tight-loop snippet。将当前行为与 pull request #2844 进行比较;完成的标准是该示例不再将循环压缩为只有第一个值和最后一个值。

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描述

Original code: https://javascript.info/call-apply-decorators#throttle-decorator

Here's a small code snippet to show where it doesn't work.

function f(a) { console.log(a) };

let g = throttle(f, 1000);

for(let i = 0; i < 1e8; i++) g(i);
Expected Output

1, 249204, 452039, ... , 9999999 (These are random increasing numbers)

Output

1, 9999999

Why does it fail?
function wrapper() {

    if (isThrottled) { // (2)
      savedArgs = arguments;
      savedThis = this;
      return;
    }
    isThrottled = true;

    func.apply(this, arguments); // (1)

    setTimeout(function() {
      isThrottled = false; // (3)
      if (savedArgs) {
        wrapper.apply(savedThis, savedArgs);
        savedArgs = savedThis = null;
      }
    }, ms);
  }

In above, isThrottled = false assignment is done inside setTimeout callback. However, only one callback is pushed into task queue and it isn't executed until stack is empty (for loop has to be completed).
isThrottled is always true => setTimeout isn't called => one callback (that was registered for initial false isThrottled) => cb executed at end and outputs last value => output: 1, 9999999.

Correct Solution: https://github.com/javascript-tutorial/en.javascript.info/pull/2844

This PR giving an alternative solution.

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