Hacktoberfest 2026:维护者为十月标记出来的 issue,仍然开放、适合新手。 浏览 Hacktoberfest issue

uint and int refuse values past the JavaScript safe-integer ceiling

未关闭
#20 0 条评论 0 个 reaction 已指派 0 人 在 GitHub 查看

还没有人认领这个 Issue。

评估

难度
3/5
预计耗时
1-2 天
新手友好度
75/100
Issue 类型
缺陷
描述清晰度
描述清楚
活跃度
活跃
技术栈
python
领域
backend

调研方向

Start with src/compact_encoding/integer.py and read how MAX_SAFE_INTEGER is applied to integer codecs. Run the conformance cases int-past-range, int-past-range-min, uint-decode-ceiling, and uint56-decode-ceiling. Done means Python integers beyond the JavaScript safe-integer ceiling encode and decode according to the expected corpus results instead of being refused.

由索引模型根据 Issue 内容生成。

描述

Found by running the compact-encoding-test conformance corpus against this port.

uint, int and the fixed-width codecs refuse values above 9007199254740991, the largest integer a JavaScript double holds exactly:

import compact_encoding as c

c.encode(c.int, 4503599627370496)                                   # ValueError: integer is greater than the maximum safe integer
c.uint.decode(c.State(bytes.fromhex('ff0000000000002000')))         # ValueError: uint is greater than the maximum safe integer
c.uint56.decode(c.State(bytes.fromhex('00000000000020')))           # ValueError: uint is greater than the maximum safe integer

The ceiling comes from MAX_SAFE_INTEGER in src/compact_encoding/integer.py, mirroring the reference. The corpus treats it as the reference's limit rather than the format's: per holepunchto/compact-encoding-test#120 and #128, int writes 4503599627370496 as ff0000000000002000 and -4503599627370497 as ff0100000000002000, and both decodes return 9007199254740992. An implementation may refuse a value its number type cannot hold (the unrepresentable outcome), but Python's int holds all of them, so the refusal is a divergence (holepunchto/compact-encoding-test#19).

The corpus cases are int-past-range and int-past-range-min (rule signed-range), and uint-decode-ceiling and uint56-decode-ceiling (rule decode-ceiling).

主要语言
Python
星标
1
派生
1
PR 合并指标
30 天内没有已合并 PR

环境准备

这个项目没有提供开发容器、Dockerfile 或贡献指南,环境需要你自己搭建:先看它的 README,通用步骤见我们的新手贡献指南。

从这里开始

  1. 先读完整个 Issue,再读项目的贡献指南。
  2. 在 Issue 下留言说明你要接手 —— 这能避免两个人做同样的事。
  3. Fork 仓库,在一个分支上完成修改。
  4. 提交 Pull Request,并在描述里引用这个 Issue 编号。

holepunchto/compact-encoding-python 的其他 Issue

查看 holepunchto/compact-encoding-python 的全部 Issue

相似的 Issue

更多 Python Issue

把新 issue 发到你的邮箱

精选适合新手参与的 GitHub issue 摘要。