Find or delete non-existing UID results to prevent an uncacheable error.

首先，使用一个不存在的 UID 调用 Firebase Auth 的 admin.auth().getUser(uid) 和 deleteUser(uid)，重现所报告的行为。检查提供的 TypeScript 函数如何处理 auth/user-not-found 错误，并确定缺失用户时的预期行为。对于查找和删除两种情况，都有记录或测试结果后，才算完成。

Platform:

• Operating System version: MacOs - Darwin 23.6.0 arm64 arm
• Firebase SDK version: 11.11.1
• Firebase Product: Firebase Auth
• Bun version: 1.2.2 (Don't think is related)
• NPM version: 10.8.2

Problem:
Whenever I try to find a user that doesn't exist or delete a uid that doesn't exist it thorws an error that breaks the function and is not cachable for some reaons, and its very weird behavirous that im not able to handle, i tried to use try catch, and then catch, but still the same. This has no steep to reprpoduce the error, its default behaviour.

Code:

import { Firebase } from '@/libs/firebase'
import { Console } from '@/helpers/logs'

const admin = await Firebase()

const DeleteFirebaseAccount = async (uid: string): Promise<boolean> => {
    try {
        const userExists = await admin.auth().getUser(uid)
        if (userExists) await admin.auth().deleteUser(uid)

        return true
    } 
    
    catch (error) {
        Console.Error('DeleteFirebaseAccount', error)
        return false
    }
}

export default DeleteFirebaseAccount

The error:

class FirebaseError extends Error {
29 |     constructor(errorInfo) {
30 |         super(errorInfo.message);
             ^
error: There is no user record corresponding to the provided identifier.
  errorInfo: {
  code: "auth/user-not-found",
  message: "There is no user record corresponding to the provided identifier.",
},
 codePrefix: "auth",