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`in` operator on a struct doesn't respect `expr` tags

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评估

难度
3/5
预计耗时
1-2 天
新手友好度
65/100
Issue 类型
缺陷
描述清晰度
描述清楚
活跃度
活跃
技术栈
go
领域
backend

调研方向

The issue is about the 'in' operator not respecting struct field tags. Start by examining the parser and evaluator for the 'in' operator, likely in the 'parser' and 'eval' packages. Look at how struct field access is resolved, comparing the handling of field names vs. 'expr' tags. The provided playground link shows the exact test case; run the tests in the repository to see existing behavior and add a test for this bug. Check for similar issues around struct field tag handling to understand the codebase patterns.

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描述

While the documentation doesn't say that the in operator can be used on structs, it does actually work.
However it doesn't respect the expr tag and instead checks membership using the struct's go field names.

Example

With an environment built from:

type Outer struct {
	Inner map[string]struct{} `expr:"bar"`
}
type Env struct {
	Outer Outer `expr:"foo"`
}

in operator:
"bar" in foo => false
"Inner" in foo => true

Field access behaves the opposite:
foo.bar => map[]
foo.Inner => compilation error

Playground: https://go.dev/play/p/GqjjiidBOx0

主要语言
Go
星标
8k
派生
529
30 天内没有已合并 PR

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  3. Fork 仓库，在一个分支上完成修改。
  4. 提交 Pull Request，并在描述里引用这个 Issue 编号。

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