Untyped action usage bound to an invocation does not resolve the invoked action's parameters
维护者通常 1 天内回复
还没有人认领这个 Issue。
评估
调研方向
Start by reproducing the issue with the sysml -action I::caller inherited.sysml command and compare it with the explicitly typed run : Base form. Trace member lookup and inferred typing for an action usage whose value is an invocation expression. Done means run.r resolves without an explicit type and the model executes with result = 7.
由索引模型根据 Issue 内容生成。
描述
Summary
An action usage whose value is an invocation expression, written without an explicit type, does not expose the invoked action's parameters to member access. Validation reports unresolved member for a parameter that the invoked definition declares, and the model cannot be executed.
Reproduction
package I {
private import ScalarValues::*;
action def Base {
in x : Integer = 3;
in z : Integer = x * 2;
out r : Integer;
first start;
then assign x := 10;
then assign r := z;
then done;
}
action caller {
out attribute result : Integer;
first start;
then action run = Base(x = 3, z = 7);
then action keep { assign result := run.r; }
then done;
}
}
$ sysml -action I::caller inherited.sysml
inherited.sysml:17:45: error: unresolved member: r
then action keep { assign result := run.r; }
^
sysml: inherited.sysml did not analyse cleanly; no check was made
The result is the same on develop at 3d45ca6fb.
Expected
run is the result of Base(x = 3, z = 7), which is typed by Base, so run.r resolves to Base::r and the model runs with result = 7.
Writing the type explicitly, then action run : Base = Base(x = 3, z = 7);, resolves run.r and runs with result = run.r = run.z = 7. That suggests the member lookup on run does not use the type implied by its invocation value.
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