Correct approach to compare `ResolvedType` with a raw `Class<?>`?
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调研方向
从 issue 中提到的 ResolvedType 和 TypeResolver API 开始，尤其是 resolve、getTypeParameters、getErasedType 和 equals。复现 GenericType 示例，并比较 raw-Class 和 resolved-type 两种方法；完成后应明确建议如何检查 resolved type 是否为 String，包括任何相关的 overhead。
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描述
What's the appropriate way to see if a ResolvedType represents a simple class that I know about?
Let's say I pass a new GenericType<String>{} to a method, and I just want to see if the generic parameter is String. I think (I haven't tried it yet) I would do this (code not optimized, for illustration):
void foo(GenericType<?> genericType) {
TypeResolver typeResolver = new TypeResolver();
ResolvedType resolvedType = typeResolver.resolve(genericType);
How would I then see if resolvedType indicates a simple String? I'm guessing I could do this:
if(resolvedType.getTypeParameters.isEmpty() && resolvedType.getErasedType().equals(String.class)) {
…
But that seems sort of awkward. Is there a better way?
(Note that the resolvedType.getTypeParameters.isEmpty() check is arguably not necessary here, as String has no generic parameters, but I'm looking for a general approach.)
Or should I be going in the other direction, resolving String.class and then comparing the resolved types?
if(resolvedType.equals(typeResolver.resolve(String.class))) {
…
I don't know how much overhead the extra resolution of String.class adds, though.
This may be related to #31.
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