`SoftwareCatalogApi.list_catalog_entity` does not filter services when `filter_name` is passed
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评估
- 难度
- 3/5
- 预计耗时
- 1-2 天
- 新手友好度
- 38/100
- Issue 类型
- 缺陷
- 描述清晰度
- 基本清楚
- 活跃度
- 停滞
- 技术栈
- openapi, python
调研方向
从 SoftwareCatalogApi.list_catalog_entity 入口点开始,使用 filter_name="service:<app_name>" 和 filter_kind="service" 重现请求。跟踪筛选器的发送方式,并根据预期服务验证响应;当提供 filter_name 时 API 返回所请求的服务,即表示完成。
由索引模型根据 Issue 内容生成。
描述
Describe the bug
I have tried to pass in variations of filter_name such as filter_name=app_name, filter_name=f"name:{app_name}", and filter_name=f"service:{app_name}". The results always return the services in alphabetical order. I have verified the services I'm filtering exist.
Label the issue properly.
- Add
severity/label. - Add
documentationlabel if this issue is related to documentation changes.
To Reproduce
Steps to reproduce the behavior:
def associate_datadog_teams(app_name: str, owner: str) -> str:
if not app_name or not isinstance(app_name, str):
raise ValueError("Invalid app_name provided")
if not owner or not isinstance(owner, str):
raise ValueError("Invalid owner provided")
# Make sure application key is available under the env var the SDK expects
if os.getenv("DD_APP_KEY") is None and os.getenv("DD_APPLICATION_KEY"):
os.environ["DD_APP_KEY"] = os.environ["DD_APPLICATION_KEY"]
# Validate required credentials are present
if not os.getenv("DD_API_KEY") or not os.getenv("DD_APP_KEY"):
raise ValueError(
"Missing Datadog credentials. Ensure DD_API_KEY and DD_APP_KEY (or DD_APPLICATION_KEY) are set."
)
# Helper for safely getting nested attributes whether SDK returns models or dicts
def _get(obj, path: list[str], default=None):
cur = obj
for key in path:
if cur is None:
return default
if isinstance(cur, dict):
cur = cur.get(key)
else:
cur = getattr(cur, key, None)
return cur if cur is not None else default
# Search for service by exact name
configuration = Configuration()
with ApiClient(configuration) as api_client:
api = SoftwareCatalogApi(api_client)
try:
resp = api.list_catalog_entity(filter_name=f"service:{app_name}", filter_kind="service", page_limit=5)
except Exception as e:
raise ValueError(f"Failed to query Datadog Software Catalog: {e}") from e
print("Services returned by API:")
for item in resp.data:
service_name = item.attributes.name
print(f" - {service_name}")
print()
items = _get(resp, ["data"], [])
# Find an exact name match among returned items
matched = None
for it in items or []:
name = _get(it, ["attributes", "name"]) or _get(it, ["attributes", "metadata", "name"]) # fallback
if name == app_name:
matched = it
break
if not matched:
return f"Service '{app_name}' not found in Datadog Service Catalog. Skipping association."
Expected behavior
It should return the service I'm passing as filter_name.
Screenshots
If applicable, add screenshots to help explain your problem.
Environment and Versions (please complete the following information):
A clear and precise description of your setup:
datadog_api_client==2.40.0
- 主要语言
- Python
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