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Motivation behind not being able to get IO's content, and IO-wrapped interfacing with unwrapped (normal) code

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評估

難度
5/5
預估耗時
一週以上
新手友好度
25/100
Issue 類型
文件
描述清晰度
需要釐清
活躍度
停滯
技術堆疊
python
領域
backend

研究方向

從 issue 中提到的文件和 IO 相關進入點開始,尤其是 unsafe_perform_io,以及包裝的 Python 程式碼與標準 Python 程式碼之間的區別。釐清隱藏 IO 內容的理由,並記錄 IO 包裝操作與一般 Python 程式碼之間受支援的界線。

由索引模型根據 Issue 內容生成。

描述

Hi! Question(s) on IO.

I am trying to write a little wrapper for some stateful operation (imagine I have to do IO from/to a file), and I found out that IO containers are designed to hide their content. It's impossible to get the value of, say, a successful read result (nothing like IOSuccess.unwrap()), unless one uses unsafe_perform_io.

What is the rationale behind this design? I am asking because I am not familiar with writing typed functional code, and I could not find a motivation in the documentation for why it shouldn't be possible to get the raw content of an IO container.


Second question related to interface between IO-wrapped code and normal "unsafe" code:

Let's say I am writing code A where want to mark and wrap all IO operations. Now, code A has to interface with standard python code B. What choices do I have to make them talk?

Do I have to unwrap all my operations with unsafe_perform_io, in case I want to do something simple like getting a string from my wrapped code? Do I have to rewrite code B by making it all safe and IO-wrapped, so that they can communicate with no "unsafe" bridge between them?

It seems that in such scenario I would end up with code pieces that are of "different colors" - using the usual async-vs-sync metaphore of incompatible red and blue code -, and I would be forced to make everything of the same color.

(Here "red code" = "python code written in railway style" and "blue code" = "standard procedural python code").

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