Render unsafe latex html string using Html View

從 HtmlView 的 html 屬性和 Angular [html] binding 路徑開始；報告中的失敗是傳入 DomSanitizer 的信任值時出現 value.search is not a function。使用提供的 KaTeX HTML 重現問題，並透過在沒有例外或安全值警告的情況下進行 render，同時保留預期的標記，來確認完成。

Environment
Provide version numbers for the following components (information can be retrieved by running tns info in your project folder or by inspecting the package.json of the project):

• CLI: "@angular/compiler-cli": "~18.0.0",
• Cross-platform modules:
• Android Runtime: "@nativescript/android": "8.8.1-next.2024-07-19-10014251437",
• iOS Runtime:
• Plugin(s): "katex": "^0.16.11",, "@types/katex": "^0.16.7",
• NativeScript-Angular: "@nativescript/angular": "^18.0.0",
• Angular: "@angular/core": "~18.0.0",

Describe the bug

I created unsafe html string using

this._safeHtml = this.domSanitizer.bypassSecurityTrustHtml(htmlString);

Attempting to render this content using Html View using property binding like so

<HtmlView [html]="_safeHtml"></HtmlView>

results to the following error

An uncaught Exception occurred on "main" thread.
Calling js method onCreateView failed
TypeError: value.search is not a function

StackTrace:
[html:setNative]...

NB:

• Using the approach below:
  <HtmlView html="{{_safeHtml}}"></HtmlView>

does not render the string(latex string) as expected and also throws a safevalue must use [property]=binding error on the screen.

• The string renders as expected in pure angular project using the following code:
  <div [innerHTML]="_safeHtml"></div>

A sample string to be rendered looks like so
<span class="katex"><math xmlns="http://www.w3.org/1998/Math/MathML" display="block"><semantics><mrow><mi>s</mi><mi>u</mi><msubsup><mi>m</mi><mrow><mi>i</mi><mo>=</mo><mn>1</mn></mrow><mi>n</mi></msubsup><mo stretchy="false">(</mo><msubsup><mi>x</mi><mi>i</mi><mn>2</mn></msubsup><mo>−</mo><mi>o</mi><mi>v</mi><mi>e</mi><mi>r</mi><mi>l</mi><mi>i</mi><mi>n</mi><mi>e</mi><msup><mi>x</mi><mn>2</mn></msup><mo stretchy="false">)</mo></mrow><annotation encoding="application/x-tex">sum_{i=1}^n(x_i^2 - overline{x}^2)</annotation></semantics></math></span>

What could be a recommended way to solve this situation or a walkaround?

To Reproduce

Expected behavior

Sample project

Additional context