Need help with an infinite loop

Bắt đầu với hàm sum_fivers() và chạy các ví dụ đã được chú thích của hàm, sau đó theo dõi điều kiện vòng lặp và các biến mà nó sử dụng. Hoàn thành nghĩa là xác định được nguyên nhân khiến quá trình thực thi không kết thúc và xác nhận hành vi mong đợi đối với các đầu vào ví dụ.

I'm taking a first time programming class and I think I have an infinite loop in my code but can't find it, can anyone help?

Here's the code:
###############################################
#Name:
#Assignment: PA6 -
#Due Date: Wednedday October 13th
#Honor Code Statement: Honor Code Statement: I received no assistance on this
#assignment that violates the ethical guidelines set forth by the professor
#and class syllabus,including any AI or code auto-complete tools.
###############################################

#######################################

Task 1: Write a function called sum_up() that takes an integer and adds up and returns all the integers for 1 up to that number.

#######################################
def sum_up(n):
current_sum = 0
counter = 1
while counter <= n:
current_sum += counter
counter += 1
return counter
#print(sum_up(5))
#print(sum_up(9))

#######################################

Task 2: Write a function called sum_up2() that takes two integers, bottom and top, and adds up and adds up and returns

#######################################
def sum_up2(bottom,top):
total = 0
current_number = bottom
while current_number <= top:
total += current_number
current_number += 1
return total
#print(sum_up2(2,3))
#print(sum_up2(2,2))
#print(sum_up2(15,19))

#######################################

Task 3: Write a function called sum_fivers that takes in integer and adds up all the multiples of 5 that are less than or equal to

#######################################
def sum_fivers(n):
total = 0
current_multiple =5
while current_multiple <= n:
total += current_multiple
return total
#print(sum_fivers(5))
#print(sum_fivers(19))

#######################################

Task 4: Write a function called count_fivers() that takes an integer and counts and returns how many multiples of 5

#######################################
def count_fivers(n):
return n // 5
#print(count_fivers(5))
#print(count_fivers(19))
#print(count_fivers(40))

#######################################

Task 5: Write a function called power_up that takes two values, the first , base, and the second is an integer

#######################################
def power_up(base, exp):
if exp == 0:
return 1.0
result = 1.0
count = 0
if exp > 0:
while count < exp:
result *= base
count += 1
elif exp < 0:
while count > exp:
result *= base
count -= 1
result = 1.0 / result

return(result)
#print(power_up(2,3))
#print(power_up(5,5))

#######################################

Task 6: Write a function called mystery_sum that takes one integer parameter, n, and calculates a "sum"

#######################################
def mystery_sum(n):
total = 0
i = 1
while i < n:
if i % 2 == 0:
total += i**i
else:
total += i * 2
i += 1
return(total)

#print(mystery_sum(4))
#print(mystery_sum(13))

#######################################

Task 7: Write a function called mystery_sum2 that takes one integer parameter, n, and caluculates a sum as follows:

#######################################
def mystery_sum2(n):
total = 0
i = 1
while i < n:
if i % 2 == 0:
total += (i // 2) ** 2
else:
total += i ** 2
i += 1
return(total)
#print(mystery_sum2(4))
#print(mystery_sum2(13))

#######################################

Task 8: Write a function called bigger_mystery() that takes one integer parameter, n, and determines which mystery function above

#######################################

def bigger_mystery(n):
sum1 = mystery_sum(n)
sum2 = mystery_sum2(n)
if sum1 > sum2:
return "ONE"
elif sum2 < sum1:
return "TWO"
else:
return "SAME"

#print(bigger_mystery(5))
#print(bigger_mystery(20))