[Feature] De-couple Starlette from FastMCP to make it easier to implement MCP endpoints in other frameworks

Examinez l’intégration de bas niveau de MCPServer, les tool/resource/prompt managers, les décorateurs et les méthodes handler décrits dans l’issue. Comparez les paramètres spécifiques à Starlette, le transport et le routage avec la frontière FastMCPBase proposée, y compris la référence FastMCP de Context ; le travail est considéré comme terminé lorsque le code indépendant du framework conserve ces fonctionnalités, tandis que FastMCP conserve les préoccupations liées à Starlette.

If someone wanted to implement an MCP server in another framework such as Django or some other ASGI implementation, one would have to use the mcp.server.lowlevel.Server class and implement handlers for the low-level server. This means we have to sacrifice a ton of functionality from FastMCP that really has nothing to do with the python server backend. For example tool/resource/prompt managers, decorators, etc would have to be re-impemented.

It seems that these features of FastMCP could be decoupled in to a base class or mixin that handles all the tool/resource/prompt management & decorators, as well as the integration with the low-level Server. You could then extend that class to implement your own server with all the routing and request/response logic.

The proposed base class would have minimal dependencies on these framework-specific concerns:

Base Class Dependencies:

• MCPServer from mcp.server.lowlevel.server
• Tool/Resource/Prompt managers
• Basic handler methods (list_tools, call_tool, etc.)
• The decorators (@tool, @resource, @prompt)

Server-specific Responsibilities:

• Settings handling (Settings class with HTTP config)
• Transport logic (stdio vs SSE)
• Routing (custom_route, Starlette routing)

class FastMCPBase:
    """Base class or mixin with tool/resource/prompt management and core handlers"""
    
    def __init__(self, name: str, instructions: str = None):
        self._mcp_server = MCPServer(name=name, instructions=instructions)
        self._tool_manager = ToolManager()
        self._resource_manager = ResourceManager()
        self._prompt_manager = PromptManager()
        self._setup_handlers()
    
    # All the @tool, @resource, @prompt decorators
    # All the list_tools, call_tool, etc. handler methods
    # Context management

class FastMCP(FastMCPBase):
    """Starlette-specific implementation"""
    
    def __init__(self, name: str, **settings):
        super().__init__(name)
        self.settings = Settings(**settings)
        self._custom_starlette_routes = []
    
    # Only Starlette-specific methods like sse_app, routing, etc.

The implementation in the other library could look like this:

class DjangoMCP(FastMCPBase):
    """Django-specific implementation"""
    # Django-specific routing & transport logic

One slight complication could be the Context class as it has a reference to the FastMCP instance (self._fastmcp. However the only function that's used is read_resource which would already be on the base class. So possible just need to change the type hint to use the base class.