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[Feature] Allow optional permutations when exclusive matchFilters are present

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#355 0 comentarios 0 reacciones 0 asignados Ver en GitHub

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Evaluación

Dificultad
5/5
Tiempo estimado
Más de una semana
Aptitud para principiantes
25/100
Tipo de issue
Nueva funcionalidad
Claridad
Bastante claro
Estado de actividad
Estancado
Stack tecnológico
typescript
Área
frontend

Línea de trabajo

Comienza con la función expandOptionals mostrada en el issue y sigue cómo sus rutas generadas se combinan con matchFilters. Compara las expansiones ordenadas actuales con el array de rutas permutado explícitamente en el ejemplo. Se considera terminado cuando unos matchFilters mutuamente excluyentes habilitan las permutaciones opcionales equivalentes sin requerir que los llamadores enumeren manualmente cada ruta.

Escrito por el modelo de indexación a partir del texto del issue.

Descripción

enhancement
Describe the bug

I was having issues with a routing setup where I have multiple optionals in a row in a path, but each has exclusive matchFilters to differentiate them. I looked through the code and found:

export function expandOptionals(pattern: string): string[] {
  let match = /(\/?\:[^\/]+)\?/.exec(pattern);
  if (!match) return [pattern];

  let prefix = pattern.slice(0, match.index);
  let suffix = pattern.slice(match.index + match[0].length);
  const prefixes: string[] = [prefix, (prefix += match[1])];

  // This section handles adjacent optional params. We don't actually want all permuations since
  // that will lead to equivalent routes which have the same number of params. For example
  // `/:a?/:b?/:c`? only has the unique expansion: `/`, `/:a`, `/:a/:b`, `/:a/:b/:c` and we can
  // discard `/:b`, `/:c`, `/:b/:c` by building them up in order and not recursing. This also helps
  // ensure predictability where earlier params have precidence.
  while ((match = /^(\/\:[^\/]+)\?/.exec(suffix))) {
    prefixes.push((prefix += match[1]));
    suffix = suffix.slice(match[0].length);
  }

  return expandOptionals(suffix).reduce<string[]>(
    (results, expansion) => [...results, ...prefixes.map(p => p + expansion)],
    []
  );
}

And while I understand the sentiment in the comment, I believe this design should be rethought for routes where there are exclusive matchFilters for each of the optionals. For example, the case where you have:

const matchFilters = { 
  a: ["hello","world"],
  b: ["foo","bar"],
  c: /^\d+$/
}
// ...
<Route path="/:a?/:b?/:c?" matchFilters={matchFilters} /* ... */ />
// ...

There is no reason why all permutations of this route shouldn't be available, as the matchFilters for all three routes are mutually exclusive. A workaround for this is to use an array of paths with only one optional per path. When used with matchFilters this technique allows the functionality, but requires manually permuting the list of optionals to create the array -- for example the above becomes:

<Route path={["/:a/:b/:c?", "/:a/:c?", "/:b/:c?", "/:c?"]} matchFilters={matchFilters} />

which works as described.

Your Example Website or App

n/a

Steps to Reproduce the Bug or Issue

nothing to reproduce -- current functionality is working as intended, would just be nice if matchFilters were taken into account when generating optional routes

Expected behavior

When matchFilters are present, allow permutations of optional parameters as long as the matchFilters for all parameters are mutually exclusive

Screenshots or Videos

No response

Platform

n/a

Additional context

No response

Lenguaje dominante
TypeScript
Estrellas
1.3k
Forks
180
Merge medio
1 d 13 h
PR fusionados (30 d)
19

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