`codecs.StreamReader.read()` silently drops an incomplete character at the end of the stream

Abierto
#160,309 0 comentarios 0 reacciones 0 asignados Ver en GitHub

Los mantenedores suelen responder en 1 día

@saiyam-jain-dev ya está trabajando en esto.

Desde el 25/10/2026.

  • #160642 de @saiyam-jain-dev — abierto

Evaluación

Dificultad
4/5
Tiempo estimado
3-5 días
Aptitud para principiantes
56/100
Tipo de issue
Error
Claridad
Bien especificado
Estado de actividad
Activo
Stack tecnológico
python
Área
backend, testing

Línea de trabajo

Start with Lib/codecs.py around the StreamReader.read() implementation and the linked expected-failure test StreamReaderTruncationBug.test_read_reports_truncated_input from PR #160155. Compare its end-of-stream behavior with IncrementalDecoder.decode(b'', final=True) and check the reported UTF-8, UTF-16, UTF-32, and escape-codec cases. Done means truncated input raises or uses the selected error handler instead of being silently discarded.

Escrito por el modelo de indexación a partir del texto del issue.

Descripción

stdlib type-bug

Bug description

StreamReader.read() decodes with the stateless codec function and keeps any undecoded trailing bytes for the next call. When the stream is exhausted there is no next call, so an incomplete final character is neither reported nor replaced; it just disappears:

>>> import codecs, io
>>> reader = codecs.getreader('utf-8')(io.BytesIO(b'ab\xe2'))
>>> reader.read()
'ab'
>>> reader.read()
''

Every other way of decoding the same bytes either raises or applies the error handler:

>>> b'ab\xe2'.decode('utf-8')
Traceback (most recent call last):
  File "<python-input-3>", line 1, in <module>
    b'ab\xe2'.decode('utf-8')
UnicodeDecodeError: 'utf-8' codec can't decode byte 0xe2 in position 2: unexpected end of data
>>> io.TextIOWrapper(io.BytesIO(b'ab\xe2'), encoding='utf-8').read()
Traceback (most recent call last):
  ...
UnicodeDecodeError: 'utf-8' codec can't decode byte 0xe2 in position 2: unexpected end of data
>>> codecs.getreader('utf-8')(io.BytesIO(b'ab\xe2'), 'replace').read()
'ab'
>>> b'ab\xe2'.decode('utf-8', 'replace')
'ab�'

So with errors='strict' a truncated file reads as if it were well-formed, and with 'replace' the replacement character that would mark the damage is missing. The same happens with utf-16, utf-32 and the escape codecs (unicode_escape with a trailing backslash); the CJK codecs are not affected, because their stateless decoders raise on an incomplete sequence themselves.

The cause is in read(): self.decode is the codec's stateless function with its default final=False (Lib/codecs.py line 512), and the loop exits on empty newdata without ever telling the decoder that the input is complete; self.bytebuffer keeps the fragment forever. Fixing it would mean a final decode pass once the underlying stream returns nothing, and raising (or applying the handler) if bytes remain, which is what IncrementalDecoder.decode(b'', final=True) does. The incremental decoders did not exist when StreamReader was written, which I assume is how this came about.

I realise codecs.open() is deprecated since 3.14 and StreamReader is on its way out with it, so feel free to say this is not worth touching; but it is silent data loss in the strict mode, which seemed worth having on record.

This is the same mechanism as #56717 (bpo-12508, 2011), which describes it for UTF-8 with errors='replace' and has had no activity since; I am filing it anyway because it applies to every codec with multi-byte characters and the strict-mode data loss is the part that matters, but feel free to fold this into that one.

Found by the Hypothesis tests in #160155, where it is pinned as StreamReaderTruncationBug.test_read_reports_truncated_input under expectedFailure.

CPython versions tested on

CPython main (6e1bd24e4d8)

Operating systems tested on

Linux

Lenguaje dominante
Python
Estrellas
77.8k
Forks
37.7k
Merge medio
15 h 24 min
PR fusionados (30 d)
728

Preparar el entorno

Abrir en Codespaces

Inicia el contenedor de desarrollo del proyecto en tu navegador, con tu propia cuenta de GitHub.

Primeros pasos

  1. Lee el issue completo y luego la guía de contribución del proyecto.
  2. Comenta en el issue que vas a ocuparte — evita que dos personas hagan lo mismo.
  3. Haz un fork del repositorio y trabaja en una rama.
  4. Abre un pull request que haga referencia al número del issue.

Más de python/cpython

Todos los issues de python/cpython

Issues similares

Más issues de Python

Recibe los nuevos issues en tu correo

Un resumen breve de issues de GitHub para principiantes.