input_output: "the solution $X$" should be $x$, and the first figure's label has + a_{12}x_2 where the inequality has −
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- Tech stack
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Research direction
Read lectures/input_output.md at the cited lines 189, 210, 246, and 253. Check the two expressions against the equation and figure, then update the sign in the figure label and capitalize the solution variable as lowercase x. Done when both English text corrections are present.
Written by the indexing model from the issue text.
Description
Two slips in lectures/input_output.md, both on main at 530ede2. Every translation carries them, so they start in the English.
| Line | Now | Should be |
|---|---|---|
| 253 | To assure that the solution $X$ of {eq}`eq:inout_2` is a positive vector |
the solution $x$: eq:inout_2 solves for the lowercase vector, x = (I -A)^{-1} d \equiv L d (line 246) |
| 210 | ax.text(130, 38, r"$(1-a_{11})x_1 + a_{12}x_2 \geq d_1$", size=10) |
r"$(1-a_{11})x_1 - a_{12}x_2 \geq d_1$", as the inequality the figure draws has it: (1 - a_{11}) x_1 - a_{12} x_2 & \geq d_1 (line 189) |
A blind review of seven Chinese translations of the lecture found them, in B12 of QuantEcon/project-benchmarks-translation (2026-11-06), and they were checked by hand against the English.
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