zsh-users/zsh-syntax-highlighting

Highlight semicolon that doesn't terminate a sublist

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#569 opened on Oct 24, 2018

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Improvementgood first issueresolution:if-and-when-neededsyntax:command-word

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Description

false && ; foo does not execute foo because ; is equivalent to \n. Highlight it accordingly, differently to a ; that terminates a sublist.

See also workers/43726.

Contributor guide

Research direction
Understand the Zsh parser's handling of semicolons in sublists and modify the highlighting logic to differentiate between semicolons that terminate a sublist and those that do not.
Tech stack
shell
Domain
developer experience
Issue type
Bug
DifficultyEstimated implementation difficulty for a new contributor, from 1 for very small changes to 5 for expert-level work.
3
Estimated timeA rough time range for an experienced contributor to investigate, implement, test, and prepare a pull request.
1-3 hours
Activity statusHow available the issue appears right now: fresh, active, stale, blocked, or waiting on maintainer input.
Active
ClarityHow clearly the issue explains the expected change, acceptance criteria, and next step.
Clear
Prerequisites
ZshShell
Newbie friendlinessA 1-100 score estimating how approachable this issue is for first-time contributors.
60