z-pattern-matching/z

does not work with typescript

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#35 创建于 2017年12月1日

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 (3 评论) (0 反应) (0 负责人)JavaScript (1,714 star) (78 fork)batch import
bughelp wanted

描述

Strange but when I use some of the snippets with typescript, it always returns the result of the first param. For example

import {matches} from 'z';

const person = { name: 'Maria' }
matches(person)(
  (x = { name: 'John' }) => console.log('John you are not welcome!'),
  (x)                    => console.log(`Hey ${x.name}, you are welcome!`)
)

returns John you are not welcome.

贡献者指南

技术栈
javascripttypescript
领域
full stack
议题类型
bug
难度面向新贡献者的预计实现难度，1 表示很小改动，5 表示专家级工作。
3
预计时间有经验贡献者完成调查、实现、测试并准备 pull request 的粗略时间范围。
1-3 hours
活动状态议题当前的可参与程度：新鲜、活跃、陈旧、阻塞或等待维护者输入。
stale
清晰度议题是否清楚说明期望改动、验收标准和下一步。
mostly clear
前置要求
basic understanding of TypeScript type inference
新手友好度1-100 的估计分数，表示该议题对首次贡献者的友好程度。
40
研究方向
Investigate the source code of the z library, particularly the `matches` function and how it handles TypeScript type bindings. Look for any type guard or conditional types that might cause the first case to always match. Check the library's type definitions and test files for similar patterns.