mesonbuild/meson

TAP implementation issue

Open

#6,810 创建于 2020年3月20日

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 (2 评论) (2 反应) (0 负责人)Python (4,978 star) (1,465 fork)batch import
buggood first issuetest targets

描述

Describe the bug

The TAP protocol states: Any output line that is not a version, a plan, a test line, a diagnostic or a bail out is considered an “unknown” line. A TAP parser is required to not consider an unknown line as an error

Yet, the meson TAP parser does: yield self.Error('unexpected input at line %d' % (lineno,))

贡献者指南

技术栈
python
领域
testing
议题类型
bug
难度面向新贡献者的预计实现难度，1 表示很小改动，5 表示专家级工作。
2
预计时间有经验贡献者完成调查、实现、测试并准备 pull request 的粗略时间范围。
under 1 hour
活动状态议题当前的可参与程度：新鲜、活跃、陈旧、阻塞或等待维护者输入。
stale
清晰度议题是否清楚说明期望改动、验收标准和下一步。
clear
前置要求
PythonTAP protocol
新手友好度1-100 的估计分数，表示该议题对首次贡献者的友好程度。
85
研究方向
Locate the TAP parser in the meson repository (likely in mesonbuild/mesonbuild/tap.py or similar). The line `yield self.Error('unexpected input at line %d' % (lineno,))` should be replaced with a warning or a skipped line to comply with the TAP specification. Check for existing tests related to TAP parsing to verify the change. Consider adding a test case for unknown lines to ensure correct behavior.