facebookarchive/caffe2

Accuracy requires INT32 while OneHot requires INT64

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#1,402 创建于 2017年10月30日

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enhancementhelp wanted

描述

The operator Accuracy() takes parameter labels as type core.DataType.INT32. OneHot() takes parameter indices as type core.DataType.INT64. LabelCrossEntropy() takes label as type core.DataType.INT32. It's a bit waste of time to cast the label back and forth, hope there is alignment. Thx.

贡献者指南

技术栈
pythoncpp
领域
machine learning
议题类型
feature
难度面向新贡献者的预计实现难度，1 表示很小改动，5 表示专家级工作。
3
预计时间有经验贡献者完成调查、实现、测试并准备 pull request 的粗略时间范围。
1-3 hours
活动状态议题当前的可参与程度：新鲜、活跃、陈旧、阻塞或等待维护者输入。
stale
清晰度议题是否清楚说明期望改动、验收标准和下一步。
clear
前置要求
understanding of Caffe2 operator API
新手友好度1-100 的估计分数，表示该议题对首次贡献者的友好程度。
50
研究方向
The Accuracy operator expects INT32 labels while OneHot expects INT64 indices, causing a type mismatch. To resolve, examine the source files for AccuracyOp, OneHotOp, and LabelCrossEntropyOp in the caffe2/operators directory to understand their label parameter types. Then propose a consistent type (e.g., change OneHot to use INT32) and update the corresponding tests and documentation. The single comment on the issue may provide additional context.
Accuracy requires INT32 while OneHot requires INT64 · facebookarchive/caffe2#1402 | Good First Issue