Microsoft/TypeScript

Interface type coercion fails with unsatisfied properties in unions

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#59,716 创建于 2024年8月22日

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 (1 评论) (1 反应) (0 负责人)TypeScript (6,726 fork)batch import
BugDomain: check: Type InferenceHelp Wanted

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描述

🔎 Search Terms

interface type coercion type coercion unsatisfied union constraints property missing in but required conditional interference

🕗 Version & Regression Information

  • This is the behavior in every version I tried, and I reviewed the FAQ for entries about type coercion

⏯ Playground Link

https://www.typescriptlang.org/play/?#code/JYOwLgpgTgZghgYwgAgILIN4Chm+QZ0gAcAuZARiwF8stRJZEUAhTHPQiU5AJmtvrR4SZMwD6AUQAeYZBBkQQAE3yi2eAsTJ8N8sFDj4yAIgBu0AJ7IEAexsAbY-yxgLRFAGViyALwVkAD68Lm4oAMI2IPgArgC20L5ogcgAFKxB4tJgAJQA3LS2UbIw0SAIiSnZZF5cvgB8yACycGAAFgB0Bso2sZXIDQAM7QCsyAD8vMhk5PmFhNaRMfFQFQDurS0Q5lBkEVFx0Nn1mMg0BYuynESJJWWV+VgA9I-IgKDkyKs2UADW+HQwKSuvh8fnIR2wGjmBygKQwmlqVGy1Dk9nwKAheChy1h8OuiOcz2QgBlyZDwYCorBY6A4oGIoA

💻 Code

interface A {
    step: 1
}

interface B {
    step: 2
}

interface B_Ext extends B {
    step: 2
    extras: "very cool"
}

type Step = 1 | 2
type Consumer = A | (B | B_Ext);

const func = (): Step => Math.random() > 0.5 ? 2 : 1;
const consumer = (whatever: Consumer) => { }


const step = func();

// ✅ works
if(step === 1) {
    consumer({ step })
} else {
    consumer({ step })
}

// ❌ fails
consumer({ step })

🙁 Actual behavior

The compiler expects that all properties of a sub-constituent be satisfied

🙂 Expected behavior

The union defines that it is either A | B and B might be B or B & Extras

Additional information about the issue

The same happens with types instead of interfaces as well as a the extras being passed as union of the type:

// causes the same issues
type A = { step: 1 }
type B = { step: 2 } & ({} | { extras: 'very good' })

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