描述

function* sample() {
    const a = yield 1 // error, as expected, a is implicitly any
    const { b } = yield 1 // no error, but expected, b is implicitly any
    const [c] = yield 1 // no error, but expected, c is implicitly any
}

贡献者指南

技术栈

typescript

领域

backenddeveloper experience

议题类型

bug

难度面向新贡献者的预计实现难度，1 表示很小改动，5 表示专家级工作。

3

预计时间有经验贡献者完成调查、实现、测试并准备 pull request 的粗略时间范围。

half day

活动状态议题当前的可参与程度：新鲜、活跃、陈旧、阻塞或等待维护者输入。

stale

清晰度议题是否清楚说明期望改动、验收标准和下一步。

clear

前置要求

TypeScriptgeneratorsdestructuringimplicit any types

新手友好度1-100 的估计分数，表示该议题对首次贡献者的友好程度。

20

研究方向

The issue is that implicit any errors are not reported when destructuring the result of a yield expression in a generator. The fix likely involves extending the existing logic that reports implicit any for a bare yield (as implemented in issue #41348). Look at the type checker (src/compiler/checker.ts) to find where yield expressions are checked and ensure destructuring patterns are also considered. Examine the check for 'yield' result type and propagate the implicit any error through destructuring. Also, add or modify test cases in tests/cases/compiler/ to cover this scenario. The related issue and linked PR for #41348 can provide guidance on the expected changes.