JuliaLang/julia

== for immutables should recursively call == on its fields

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#4,648 创建于 2013年10月26日

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 (60 评论) (44 反应) (1 负责人)Julia (48,709 star) (5,773 fork)batch import
breakingequalityhelp wantedneeds decision

描述

This doesn't make much sense:

julia> immutable Foo{T}
         bar::T
       end

julia> Foo("baz") == Foo("baz")
false

julia> Foo("baz").bar == Foo("baz").bar
true

julia> Foo(1) == Foo(1)
true

If the fields are == to each other then the objects should be == to each other.

贡献者指南

技术栈
无
领域
backend
议题类型
bug
难度面向新贡献者的预计实现难度，1 表示很小改动，5 表示专家级工作。
3
预计时间有经验贡献者完成调查、实现、测试并准备 pull request 的粗略时间范围。
1-2 days
活动状态议题当前的可参与程度：新鲜、活跃、陈旧、阻塞或等待维护者输入。
stale
清晰度议题是否清楚说明期望改动、验收标准和下一步。
clear
前置要求
Julia immutable typesJulia's == operator behaviorRecursive comparison
新手友好度1-100 的估计分数，表示该议题对首次贡献者的友好程度。
45
研究方向
The issue indicates that for immutable types, the == operator currently compares by identity rather than by field values. The fix would involve modifying the definition of == for immutable structs to recursively compare each field using ==. Relevant files likely include the base definition of == in Julia's core library, possibly in 'base/operators.jl' or similar. The discussion in the 60 comments may provide insights into potential implementation strategies and edge cases.