shelljs/shelljs

find() should work like find(1)

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#114 建立於 2014年4月4日

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 (1 留言) (0 反應) (0 負責人)JavaScript (14,062 star) (777 fork)batch import
bash compatfixhelp wantedlow priority

描述

I expected the following to work... but took a look at the docs and require('shelljs').find quite a bit different than I expected.

Here is what I'm trying to do:

// find all directories in the cwd that have a package.json
var sh = require('shelljs');
var packages = sh.find('*/package.json').map((f) => {
 return path.dirname(f)
});

This is obviously not possible with sh.find. You have to do something like

sh.find('.').filter((p) => {
  return path.dirname(p) === cwd
      && path.filename(p) === 'package.json'
});

Would be nice if it supported the same functionality as find(1).

貢獻者指南

技術棧
javascriptnodejsshell
領域
clideveloper experience
議題類型
feature
難度面向新貢獻者的預計實作難度，1 表示很小改動，5 表示專家級工作。
3
預計時間有經驗貢獻者完成調查、實作、測試並準備 pull request 的粗略時間範圍。
half day
活動狀態議題目前的可參與程度：新鮮、活躍、陳舊、阻塞或等待維護者輸入。
stale
清晰度議題是否清楚說明預期改動、驗收標準和下一步。
clear
前置要求
basic Node.jsfamiliarity with shelljsunderstanding of file paths
新手友善度1-100 的估計分數，表示該議題對首次貢獻者的友善程度。
60
研究方向
Look at the current implementation of find() in shelljs (likely in src/find.js). Currently, find() recursively lists all files and directories. To support pattern matching like find(1), you would need to accept a pattern string and filter results accordingly. Consider using the path module or a glob library like minimatch. Check how shelljs handles patterns in other commands like ls() or test() for consistency.