josdejong/mathjs

simplify `sqrt(x)*sqrt(x)`

Open

#3,231 建立於 2024年7月10日

在 GitHub 查看
 (4 留言) (0 反應) (0 負責人)JavaScript (13,832 star) (1,298 fork)batch import
featurehelp wanted

描述

I asked it to simplify sqrt(x)*sqrt(x) and it couldn't do it. Nor could it do really anything with sqrt. As soon as I added the following single rule, it works perfectly and does all the things you would hope it should know how to do!

const simpRules = [...(math.simplify.rules)];
simpRules.push('sqrt(n1) -> n1^0.5');
math.simplify(exp,simpRules);

I suggest adding 'sqrt(n1) -> n1^0.5' to simplify.js

貢獻者指南

技術棧
javascriptnodejs
領域
backendtooling
議題類型
feature
難度面向新貢獻者的預計實作難度，1 表示很小改動，5 表示專家級工作。
2
預計時間有經驗貢獻者完成調查、實作、測試並準備 pull request 的粗略時間範圍。
under 1 hour
活動狀態議題目前的可參與程度：新鮮、活躍、陳舊、阻塞或等待維護者輸入。
fresh
清晰度議題是否清楚說明預期改動、驗收標準和下一步。
clear
前置要求
JavaScript
新手友善度1-100 的估計分數，表示該議題對首次貢獻者的友善程度。
85
研究方向
The issue asks to add a simplification rule for sqrt. The current implementation in simplify.js does not include a rule to transform sqrt(n) to n^0.5. A contributor can locate the simplify.js file in the source code, find the array of rules, and append the rule 'sqrt(n1) > n1^0.5' (or equivalent using math.js's rule syntax). The existing rule set can be extended by adding this single rule. Testing should include verifying that sqrt(x)*sqrt(x) simplifies to x.