glideapps/quicktype
converting a recursive json schema into a zod type breaks
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#2,508 建立於 2024年2月16日
TS Zodbuggood first issueinput:JSON Schema
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描述
example self referential schema:
{
"id": "http://json-schema.org/geo",
"$schema": "http://json-schema.org/draft-06/schema#",
"description": "A geographical coordinate",
"type": "object",
"definitions":{
"Mydef1":{
"type":"object",
"properties":{
"test":{
"$ref":"#/definitions/Mydef1"
}
}
}
},
"properties": {
"latitude": {
"$ref":"#/definitions/Mydef1"
}
}
}
produces:
export const Mydef1Schema = z.object({
"test": z.union([Mydef1Schema, z.null()]).optional(),
});
export type Mydef1 = z.infer<typeof Mydef1Schema>;
export const CoordinateSchema = z.object({
"latitude": z.union([Mydef1Schema, z.null()]).optional(),
});
export type Coordinate = z.infer<typeof CoordinateSchema>;
but it should be https://github.com/colinhacks/zod#recursive-types
=> z.lazy(() => Mydef1Schema)
export const Mydef1Schema = z.object({
"test": z.union([z.lazy(() =>Mydef1Schema), z.null()]).optional(),
});
export type Mydef1 = z.infer<typeof Mydef1Schema>;
export const CoordinateSchema = z.object({
"latitude": z.union([Mydef1Schema, z.null()]).optional(),
});
export type Coordinate = z.infer<typeof CoordinateSchema>;