apache/openwhisk

List Rule needs status field.

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#4,438 建立於 2019年4月11日

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 (5 留言) (0 反應) (0 負責人)Scala (6,777 star) (1,177 fork)batch import
APIenhancementhelp wanted

描述

Hi Guys, As I know, the response data when get list rule like below so we need return response for list rule with status(active/inactive) for each object rule.

[
        {
            "action": {
                "name": "action01",
                "path": "myspace"
            },
            "annotations": [],
            "name": "action01_trigger1",
            "namespace": "myspace",
            "publish": false,
            "trigger": {
                "name": "trigger1",
                "path": "myspace"
            },
            "version": "0.0.1"
          **//missing status ???**
        }

    ]

Any help for improve this? Thanks

貢獻者指南

技術棧
scala
領域
backendapi
議題類型
feature
難度面向新貢獻者的預計實作難度，1 表示很小改動，5 表示專家級工作。
2
預計時間有經驗貢獻者完成調查、實作、測試並準備 pull request 的粗略時間範圍。
under 1 hour
活動狀態議題目前的可參與程度：新鮮、活躍、陳舊、阻塞或等待維護者輸入。
stale
清晰度議題是否清楚說明預期改動、驗收標準和下一步。
clear
前置要求
Basic Scala knowledgeFamiliarity with REST API conceptsUnderstanding of OpenWhisk rule model
新手友善度1-100 的估計分數，表示該議題對首次貢獻者的友善程度。
60
研究方向
Look at the rule listing endpoint in the OpenWhisk controller, likely in the RulesApi or RulesResource Scala file. The response currently lacks a 'status' field; you need to add the rule's status (active/inactive) to the JSON serialization of the Rule object. Check the Rule case class and its JSON serializer to include the status field.