Microsoft/TypeScript
在 GitHub 查看Generic function passed to generic function inferred correctly only with spread
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#60,552 建立於 2024年11月21日
Domain: check: Type InferenceHelp WantedPossible Improvement
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描述
🔎 Search Terms
generic function spread regression inference
🕗 Version & Regression Information
- This is the behavior in every version I tried, and I reviewed the FAQ for entries about generics
⏯ Playground Link
💻 Code
export type Node = { };
declare function fooooooo<T, Result extends ArrayLike<unknown>, Evil extends readonly unknown[]>(
input: T,
callback: (input: T, prev: Result, ...evil: Evil) => Result,
): Result
declare function baaaaaar<T, Result extends ArrayLike<unknown>>(
input: T,
callback: (input: T, prev: Result) => Result,
): Result
declare function callback<T>(
input: T,
prev: string[],
): string[];
export function example<T>(input: T) {
// Infers type parameter Result correctly
fooooooo(input, callback);
// ^? function fooooooo<T, string[], []>(input: T…
// Fails to infer type parameter Result correctly instead infers the constraint
baaaaaar(input, callback);
// ^? function baaaaaar<T, ArrayLike<unknown>>(in…
// Bypassing inference, the function call is correct
baaaaaar<T, string[]>(input, callback);
// Infers type parameter Result correctly
baaaaaar(input, callback<T>);
// ^? function baaaaaar<T, string[]>(input: T, ca…
}
🙁 Actual behavior
baaaaaar(input, callback) infers the constraint of Result = ArrayLike<unknown>
🙂 Expected behavior
baaaaaar(input, callback) should infer Result = string[] from the return type or parameter of callback.
Additional information about the issue
No response