Microsoft/TypeScript

Generated d.ts includes implicit any for recursive types

開放

#55,832 建立於 2023年9月22日

 (9 則留言) (0 個反應) (0 位負責人)TypeScript (13,395 個分叉)batch import
Domain: Declaration EmitHelp WantedPossible Improvement

倉庫指標

星標
 (108,860 顆星)
PR 合併指標
 (PR 指標待抓取)

描述

🔎 Search Terms

recursive any noImplicitAny d.ts

🕗 Version & Regression Information

  • This is the behavior in every version I tried (3.3 through 5.2), and I reviewed the FAQ for entries about anything related to this.

⏯ Playground Link

playground link

💻 Code

const a = () => a;

🙁 Actual behavior

Any is implicitly introduced in the d.ts:

declare const a: () => any;

Note that the local type checking (not using the d.ts) correctly handles this recursive type without introducing "any", and builds fine with noImplicitAny enabled.

🙂 Expected behavior

Either generate something without implicitly introducing any, or generate an error if noImplicitAny is enabled. In this case, the below code generation for the d.ts would work:

declare const a: () => typeof a;

Additional information about the issue

No response

貢獻者指南