Fails to expand indexed access type when used as a generic type parameter
#54,776 建立於 2023年6月26日
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描述
Bug Report
This logic is part of a proprietary DSL where the user wants to work with a number of types, specified as a record. Most of the time the user calls a function similar to
declare function someOtherFunction<T extends DiscriminatorRecord>(record: T): { [K in keyof T]: DiscriminatedUnion<T[K]> }
in which case there are no problems with the inference, but sometimes T needs to be restricted to have certain keys and values, as shown in the code below. One part of the problem that I wasn't able to reproduce in a code example was the fact that it did work with four types in the union, but failed when I added a fifth. Whereas in the example it fails with any number except one. I could spend more time on reproduction, but hopefully this will be helpful to start with.
🔎 Search Terms
generic indexed access type inference
🕗 Version & Regression Information
- This is the behavior in every version (
5.0.4,5.1.3,v5.2.0-dev.20230625) I tried, and I reviewed the FAQ for entries about Type System Behavior, Generics
⏯ Playground Link
Playground link with relevant code
💻 Code
type Discriminator =
| 'First'
| 'Second'
| 'Third'
type DiscriminatedUnion<D extends Discriminator> = { discriminator: D } & (
| { discriminator: 'First', first: boolean }
| { discriminator: 'Second', second: boolean }
| { discriminator: 'Third', third: boolean }
)
type DiscriminatorRecord = Record<string, Discriminator>
function someFunction<T extends DiscriminatorRecord & { override: 'Third' }>() {
type DiscriminatorFromT = T['override'] // If this expands to 'Third'
type DiscriminatedFromLiteral = DiscriminatedUnion<'Third'> // then this
type DiscriminatedFromT = DiscriminatedUnion<DiscriminatorFromT> // should be equivalent to this
const f1 = (d: DiscriminatedFromLiteral) => d.third; // yet this works
const f2 = (d: DiscriminatedFromT) => d.third; // but not this
}
🙁 Actual behavior
const f2 = (d: DiscriminatedFromT) => d.third; fails with
Property 'third' does not exist on type 'DiscriminatedUnion<DiscriminatorFromT>'.
Property 'third' does not exist on type '{ discriminator: DiscriminatorFromT; } & { discriminator: "First"; first: boolean; }'.
🙂 Expected behavior
The property third is inferred to exist on d in const f2 = (d: DiscriminatedFromT) => d.third;