JuliaLang/julia

== for immutables should recursively call == on its fields

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#4,648 建立於 2013年10月26日

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 (60 留言) (44 反應) (1 負責人)Julia (48,709 star) (5,773 fork)batch import
breakingequalityhelp wantedneeds decision

描述

This doesn't make much sense:

julia> immutable Foo{T}
         bar::T
       end

julia> Foo("baz") == Foo("baz")
false

julia> Foo("baz").bar == Foo("baz").bar
true

julia> Foo(1) == Foo(1)
true

If the fields are == to each other then the objects should be == to each other.

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領域
backend
議題類型
bug
難度面向新貢獻者的預計實作難度，1 表示很小改動，5 表示專家級工作。
3
預計時間有經驗貢獻者完成調查、實作、測試並準備 pull request 的粗略時間範圍。
1-2 days
活動狀態議題目前的可參與程度：新鮮、活躍、陳舊、阻塞或等待維護者輸入。
stale
清晰度議題是否清楚說明預期改動、驗收標準和下一步。
clear
前置要求
Julia immutable typesJulia's == operator behaviorRecursive comparison
新手友善度1-100 的估計分數，表示該議題對首次貢獻者的友善程度。
45
研究方向
The issue indicates that for immutable types, the == operator currently compares by identity rather than by field values. The fix would involve modifying the definition of == for immutable structs to recursively compare each field using ==. Relevant files likely include the base definition of == in Julia's core library, possibly in 'base/operators.jl' or similar. The discussion in the 60 comments may provide insights into potential implementation strategies and edge cases.