[feat] Conditional routing

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#243 2 comments 3 reactions 0 assignees View on GitHub

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Assessment

Difficulty
5/5
Estimated time
Over a week
Newbie friendliness
30/100
Issue type
Feature
Clarity
Mostly clear
Activity status
Stale
Tech stack
typescript
Domain
frontend

Research direction

Start by locating the Show component and the RouteDefinition interface mentioned in the proposal, then trace how routes render component or element. Determine how conditional evaluation and fallback rendering fit the existing routing flow. Done means RouteDefinition supports when and fallback, with the specified defaults and 404 behavior when no fallback is provided.

Written by the indexing model from the issue text.

Description

enhancement

My feature request is simple, adding conditional routing. The proposal is to add two properties from the Show component into the RouteDefinition interface.

  • when: () => boolean
  • fallback: () => JSX.Element | string | Array<JSX.Element | string>

if when is not defined, use a default value that always computes to true. If the computed value of when() is false render fallback() instead of component or element.

In my opinion this allows a much cleaner syntax for creating routes that should only be available when certain conditions are met. If the conditions are not met it offers a simple way to show the end-user that some condition was not met. If fallback is not defined, treat the route as it is a 404.

Dominant language
TypeScript
Stars
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Forks
180
Avg merge
1d 13h
Merged PRs (30d)
19

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