Use syntax-span and syntax-position to compute the tail space in a list

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good first issue

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@racketblock[( a   b   cde  )]

is currently rendered as:

( a   b   cde)

The spaces between "cde" and ")" are missing.

One possible fix:

use syntax-position to find that the position of "( a .... )" is x with the span of 16
use syntax-position to find that the position of "cde" is x + 10 with the span of 3
So there should be 16 - ((x + 10) - x) - 3 - 1 = 2 spaces between "cde" and ")".
More generally: the quantity is whole-span - (last-pos - whole-pos) - last-span - 1.
The spaces must be added before ")" is written. Somewhere before https://github.com/racket/scribble/blob/bdffb99ca49ed17be8198f2376e6bf6b199cb813/scribble-lib/scribble/racket.rkt#L788

Research direction: Look at the rendering code in scribble/racket.rkt around line 788, and implement the formula for computing tail spaces using syntax span and syntax position.
Tech stack: None
Domain: documentationbackend
Issue type: Bug
Difficulty: 2
Estimated time: 1-3 hours
Activity status: Fresh
Clarity: Clear
Prerequisites: RacketScribble
Newbie friendliness: 65