Accumulate without emit/output

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Assessment

Difficulty
3/5
Estimated time
1-2 days
Newbie friendliness
35/100
Issue type
Feature
Clarity
Mostly clear
Activity status
Stale
Tech stack
python

Research direction

Start with the linked Accumulating State documentation and the accumulate and partition APIs. Reproduce the example using returns_state=True and a conditional emission, then determine whether accumulate supports suppressing output directly. Done means the requested behavior is implemented or the documentation clearly explains the supported approach, with coverage for both emitted and suppressed values.

Written by the indexing model from the issue text.

Description

According to the documentation of accumulate (Accumulating State), it is possible to not have accumulate "output" anything:

One piece of data comes in, either one or zero pieces go out.

I tried to come up with a way to use this to "group" values together: collect values as they come in and emit a list "every now and then".

Basically I have something along the lines of this now:

stream = streamz.Stream()
grouped = stream.accumulate(my_group, returns_state=True, start={}).filter(non_empty)


def my_group(state, row):
    ...
    if <condition>:
        return state, [<collected_rows>]
    else:
        return state, None

def non_empty(row):
    if row:
        return True
    return False

But I think the .filter(non_empty) part should not be necessary. I should be able to not return (output) a value unless I emit a list in my_group, no? Would that not be the "zero pieces go out" case?

Note: I realised in the meantime that I might be able to achieve what I need using partition, but the question remains (for other use cases): how can I not emit (or output) a value from accumulate?

Dominant language
Python
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