gulpjs/gulp
Ver no GitHubBetter document using ordered-read-stream to handle multiple streams being returned
Open
#1.269 aberto em 21 de set. de 2015
documentationgulp4help wanted
Métricas do repositório
- Stars
- (32.979 stars)
- Métricas de merge de PR
- (Nenhuma PRs mesclada em 30d)
Description
A really commonly asked question, and one of the recipes, is how to return multiple streams in one task. The answer is to use merge-stream, of course, but would it be easier for users / cut down the number of support questions if merge-stream were a dependency of gulp and returning an array of streams called it automatically?
So this:
var gulp = require('gulp');
var merge = require('merge-stream');
gulp.task('test', function() {
var bootstrap = gulp.src('bootstrap/js/*.js')
.pipe(gulp.dest('public/bootstrap'));
var jquery = gulp.src('jquery.cookie/jquery.cookie.js')
.pipe(gulp.dest('public/jquery'));
return merge(bootstrap, jquery);
});
Would turn into this:
var gulp = require('gulp');
gulp.task('test', function() {
var bootstrap = gulp.src('bootstrap/js/*.js')
.pipe(gulp.dest('public/bootstrap'));
var jquery = gulp.src('jquery.cookie/jquery.cookie.js')
.pipe(gulp.dest('public/jquery'));
return [bootstrap, jquery];
});
It's pretty much the same, but a lot simpler to someone who doesn't understand streams or nodejs. Also, really easy to implement.
Thoughts?