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Stepping over a false conditional breakpoint stops the stepping and just continues.

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#1,535 1 comment 0 reactions 0 assignees View on GitHub

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Assessment

Difficulty
4/5
Estimated time
3-5 days
Newbie friendliness
45/100
Issue type
Bug
Clarity
Mostly clear
Activity status
Stale
Tech stack
java, typescript
Domain
devtools

Research direction

Start by reproducing the Java example in vscode-java-debug with a false conditional breakpoint on int y = 0, then compare Step Over behavior with that breakpoint disabled. The fix is complete when stepping from foo() reaches the later x++ lines instead of continuing execution.

Written by the indexing model from the issue text.

Description

ai-triaged bug
public class DebugTest {

  public static void main(String[] args) {
    int x = 0;
    foo();
    x++;
    x++;
  }

  public static void foo() {
    int y = 0;
  }
}

With this example In put a conditional breakpoint with condition false on int y= 0. Then I put a breakpoint on int x = 0; and used Step Over. After stepping over foo I didn't hit the later lines and the program just continues. Disabling the conditional breakpoint makes stepping over work as I would expect (went from foo() to x++).

Dominant language
TypeScript
Stars
591
Forks
429
Avg merge
1d 9h
Merged PRs (30d)
19

Contributor guide

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First steps

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  3. Fork the repository and make your change on a branch.
  4. Open a pull request that references the issue number.

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