Microsoft/TypeScript

in operator typeguard precision loss

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#51,339 opened on 2022/10/28

 (2 件のコメント) (0 件のリアクション) (0 人の担当者)TypeScript (13,395 件のフォーク)batch import
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説明

Bug Report

🔎 Search Terms

🕗 Version & Regression Information

v4.9.0 v4.9.1 5.0.0-dev.20221101

⏯ Playground Link

Playground link with relevant code

💻 Code

function addressOrThrow(value: unknown) {
  if (typeof value !== "object" || value == null) throw new TypeError();

  if (!("street" in value) || typeof value.street !== "string")
    throw new TypeError();

  if (!("houseNumber" in value) || typeof value.houseNumber !== "number")
    throw new TypeError();

  return value;
}

function addressOrThrowTG(value: unknown): value is Address {
  addressOrThrow(value);
  return true;
}

function personOrThrow(value: unknown) {
  if (typeof value !== "object" || value == null) throw new TypeError();

  if (!("firstName" in value) || typeof value.firstName !== "string")
    throw new TypeError();

  if (!("lastName" in value) || typeof value.lastName !== "string")
    throw new TypeError();

  if ("middleName" in value && typeof value.middleName !== "string")
    throw new TypeError();

  if (!("addresses" in value) || !Array.isArray(value.addresses))
    throw new TypeError();

  if (!value.addresses.every(addressOrThrowTG))
    throw new TypeError();

  return value;
}

type Address = ReturnType<typeof addressOrThrow>;

type Person = ReturnType<typeof personOrThrow>;

🙁 Actual behavior

type Address = object & Record<"street", unknown> & Record<"houseNumber", unknown> type Person = object & Record<"firstName", unknown> & Record<"lastName", unknown> & Record<"addresses", unknown>

🙂 Expected behavior

type Address = object & Record<"street", string> & Record<"houseNumber", number> type Person = object & Record<"firstName", string> & Partial<Record<"middleName", string>> & Record<"lastName", string> & Record<"addresses", Address[]>

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