zsh-users/zsh-syntax-highlighting
Highlight semicolon that doesn't terminate a sublist
Aperta
#569 aperta il 24 ott 2018
Improvementgood first issueresolution:if-and-when-neededsyntax:command-word
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Descrizione
false && ; foo does not execute foo because ; is equivalent to \n. Highlight it accordingly, differently to a ; that terminates a sublist.
See also workers/43726.