zsh-users/zsh-syntax-highlighting

Highlight semicolon that doesn't terminate a sublist

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#569 aperta il 24 ott 2018

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Improvementgood first issueresolution:if-and-when-neededsyntax:command-word

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Descrizione

false && ; foo does not execute foo because ; is equivalent to \n. Highlight it accordingly, differently to a ; that terminates a sublist.

See also workers/43726.

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