Expected Behavior

When using the build command with --include-shell=false the shell script(s) should be removed from the image

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Actual Behavior

It appears as if the shell used to run the --exec script will be included in the assets to keep (probably because it is actually running at the time of analysis)

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Steps to Reproduce the Problem

1. Minimize a standard unbuntu image, do not run any script:

>~/apps/dist_linux/slim build --http-probe=false --include-shell=false ubuntu:22.04

Try to execute a shell inside the minimized image, as expected, docker will complain:

>docker run --rm -ti ubuntu.slim /bin/sh
docker: Error response from daemon: failed to create shim task: OCI runtime create failed: runc create failed: unable to start container process: exec: "/bin/sh": stat /bin/sh: no such file or directory: unknown.

2. Fake a script run:

~/apps/dist_linux/slim build --http-probe=false --include-shell=false --exec /bin/true ubuntu:22.04

Run the /bin/sh shell inside the trimmed image (you get a shell prompt):

>docker run --rm -ti ubuntu.slim /bin/sh
#

This is probably not a bug but an unexpected side-effect of the build internal implementation. Maybe an additional option like --run dedicated to run binary files bypassing the shell (like ENTRYPOINT do with its json array arguments) would clarify the intent and preserve the semantics of --include-shell ?

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Specifications

slim version linux|Transformer|1.40.3|155f1b79556b7d100726f5ef4633f81a6ed27a2b|2023-07-13_07:46:40AM

• Platform:
• Distributor ID: Ubuntu Description: Ubuntu 22.04.2 LTS Release: 22.04 Codename: jammy