mis-assigned keyword arguments when two function parameters have the same name

Environment

Python 3.9.2 fire==0.4.0

Example Script

I have the following example script.py:

import fire

class Foo:
    def __init__(self):
        print("__init__")

    def bar(self, param=0):
        print(f"bar (param={param})")
        return self

    def baz(self, param=0):
        print(f"baz (param={param})")
        return self

    def end(self):
        return "end"


if __name__ == "__main__":
    fire.Fire(Foo)

Example Usages (which demonstrate a problem)

When I use the script and provide the arguments by position, it works fine:

$ python script.py bar 3 baz 5 end
__init__
bar (param=3)
baz (param=5)
end

But when I provide the arguments by keyword, the output is different and the program brings up the command-line help text for Foo:

$ python script.py bar --param=3 baz --param=5 end
__init__
bar (param=5)
baz (param=end)

More examples:

$ python script.py bar --param=3 baz 5 end
__init__
bar (param=3)
baz (param=5)
end

$ python script.py bar 3 baz --param=5 end
__init__
bar (param=5)
ERROR: Could not consume arg: 3
Usage: fire_issue_eg.py bar 3 <command>
  available commands:    bar | baz | end

For detailed information on this command, run:
  fire_issue_eg.py bar 3 --help

Thoughts

It looks like there is a problem:

• when Fire is running through two (or more) callable objects, and each object has an identically-named parameter (in the above example, param)
• when that parameter is provided on the command line via keyword on the 2nd(+) function called (in this example, baz)